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如何更正我的index.php錯誤?

[英]How to correct my index.php error?

這是我的代碼,我正在嘗試,如果我輸入我的電子郵件並通過保存在數據庫(MySQL)中的位置,將顯示出如果我輸入正確,則表明我以該電子郵件身份登錄。 因此,我想您可以為我解決編碼方面的錯誤提供幫助,但是我是Web編程的新手,因此,如果您教我最容易理解和最簡單的方法,我將非常高興。

<?php
    $servername = "localhost";
    $username = "root";
    $password = "crazyjaguar";
    $db = "getstarted";

    // Create connection
    $conn = mysqli_connect($servername, $username, $password);

    // Check connection
    if (!$conn) {
        die("Connection failed: " . mysqli_connect_error());
    }
    echo "Connected successfully";




    if ($_SERVER["REQUEST_METHOD"] == "POST") {
    //  error_reporting(0);
        if ($_POST['email'] && $_POST['pwd']) {

            // escape
                $email = mysqli_real_escape_string($conn, $_POST['email']);
                $password = mysqli_real_escape_string($conn, $_POST['pwd']);
                // sql email and pass
                $sql = "SELECT email, password FROM gs_users";

                // query esql & espl
                $result = mysqli_query($conn, $sql);

                // fetch_array
                $row = mysqli_fetch_array($result,MYSQLI_BOTH);

                    if ($row['email'] != $email) {

                        die ("No $email registered yet!");
                    }
                    if ($row['password'] = $password) {

                        die ("Wrong $pmail!");
                    }
                        echo "You're logged in as $email";

                        mysqli_close($conn);
    }   
    }

    ?>


    <body>
    <h1>Log In</h1>

    <form action='' method='post'>

    <input type='email' name='email' placeholder='Email'>
    <input type='password' name='pwd' placeholder='Password'><br />
    <a href='forgot.php'>Forgost Password?</a><br />
    <input type='submit' name='signup' value='Signup Here!'><br />
    <input type='submit' name='login' value='LogIn'>
    </form>
    </body>

mysqli_connect函數實際上可以采用4個參數。 最后一個是數據庫名稱。

語法將是

mysqli_connect(host,username,password,dbname);

盡管數據庫名稱是可選的,即使您不提供默認數據庫也將使用。

但是,您再次指定了

$db = "getstarted";

證明您錯過了包括數據庫名稱:)

然后可以使用mysqli_select_db()選擇要查詢的數據庫。

最后,我將要求您使用PDO

在這里,我假設您要首先檢查電子郵件,如果不存在則死於消息“尚未注冊電子郵件”;如果存在,則檢查輸入密碼,如果密碼匹配,則登錄。

請使用以下代碼更改您的代碼。

<?php
    $servername = "localhost";
    $username = "root";
    $password = "crazyjaguar";
    $db = "getstarted";

    // Create connection
    $conn = mysqli_connect($servername, $username, $password, $db);

    // Check connection
    if (!$conn) {
        die("Connection failed: " . mysqli_connect_error());
    }
    echo "Connected successfully";




    if ($_SERVER["REQUEST_METHOD"] == "POST") {
    //  error_reporting(0);
        if ($_POST['email'] && $_POST['pwd']) {

            // escape
                $email = mysqli_real_escape_string($conn, $_POST['email']);
                $password = mysqli_real_escape_string($conn, $_POST['pwd']);
                // sql email and pass
                $sql = "SELECT email, password FROM gs_users where email = $email";

                // query esql & espl
                $result = mysqli_query($conn, $sql);
                if (mysqli_num_rows($result) > 0)
                {
                    $row = mysqli_fetch_array($result,MYSQLI_BOTH);
                    if ($row['password'] == $password)
                    {
                        echo "You're logged in as $email";
                    }
                    else
                    {
                        die ("Invalid password!");       
                    }
                }
                else
                {
                    die ("No $email registered yet!");
                }
        }   
    }
    mysqli_close($conn);

    ?>


    <body>
    <h1>Log In</h1>

    <form action='' method='post'>

    <input type='email' name='email' placeholder='Email'>
    <input type='password' name='pwd' placeholder='Password'><br />
    <a href='forgot.php'>Forgost Password?</a><br />
    <input type='submit' name='signup' value='Signup Here!'><br />
    <input type='submit' name='login' value='LogIn'>
    </form>
    </body>

希望這會幫助你。

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