將特定單詞附加到python文件列表中

Question

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我正在編寫一個程序，該程序從50,000個單詞的文件中讀取內容，並且需要獲取其中沒有字母'e'的單詞的百分比。 我可以使程序打印出所有不帶e的單詞，但我想將它們附加到列表中，以便獲得列表中元素的總和。 現在，每次運行時，我得到的結果都為0。 它還會產生正確的總行數。 抱歉，我不是python最好的。

f=open("hardwords.txt")

def has_no_e(f):
    words = []
    sum_words= len(words)
    total = sum(1 for s in f)
    print total
    print sum_words
    letter = 'e'
    for line in f:
        for l in letter:
            if l in line:
                break
        else:
            words.append(line)

has_no_e(f)

Answer 1

您無需收集單詞，只需數數即可。

未經測試：

total = 0
without_e = 0
with open("hardwords.txt") as f:
    for line in f:
        total = total + 1
        if not 'e' in line:
            without_e = without_e + 1

percentage = float(without_e) / float(total)

Answer 2

那這個呢：

def has_no_e():
    with open(path, "r") as f:
        words = [word.strip() for line in f.readlines() for word in line.strip().split(',')]
        words_without_e = [word for word in words if 'e' not in word]
        print len(words), words
        print len(words_without_e), words_without_e

has_no_e()

現在您只需要計算百分比

Answer 3

這樣做是這樣的：

def has_no_e(path):
    total_words = 0
    words_without_e = 0
    with open(path, "r") as f:
        for line in f:
            words = line.lower().split()
            total_words += len(words)
            words_without_e += sum("e" not in w for w in words)

    return (float(words_without_e)/total_words)*100

Answer 4

這是一種可能的方法：

with open('G:\Tmp\demo.txt', 'r') as f:
    total = 0
    count = 0
    for line in f:
        words = line.split()
        total = total + len(words)
        count = count + len([w for w in words if w.find('e') > 0])

print 'Total word:{0}, counted:{1}'.format(total, count)