[英]searching specific html table column
你好,有人可以幫我這個忙。 搜索有效,但是如何排除要搜索的最后一列? 我有三列,名字,姓氏和電子郵件。
我想要的是僅使用兩列進行搜索。 並在搜索時排除列電子郵件。 謝謝你,這是我的JavaScript代碼
<script type="text/javascript">
function doSearch() {
var searchText = document.getElementById('searchTerm').value;
var targetTable = document.getElementById('report');
var targetTableColCount;
//Loop through table rows
for (var rowIndex = 0; rowIndex < targetTable.rows.length; rowIndex++ ) {
var rowData = '';
//Get column count from header row
if (rowIndex == 0) {
targetTableColCount = targetTable.rows.item(rowIndex).cells.length;
continue; //do not execute further code for header row.
}
//Process data rows. (rowIndex >= 1)
for (var colIndex = 0; colIndex < targetTableColCount; colIndex++) {
var cellText = '';
if (navigator.appName == 'Microsoft Internet Explorer')
cellText = targetTable.rows.item(rowIndex).cells.item(colIndex).innerText;
else
cellText = targetTable.rows.item(rowIndex).cells.item(colIndex).textContent;
rowData += cellText;
}
// Make search case insensitive.
rowData = rowData.toLowerCase();
searchText = searchText.toLowerCase();
//If search term is not found in row data
//then hide the row, else show
if (rowData.indexOf(searchText) == -1)
targetTable.rows.item(rowIndex).style.display = 'none';
else
targetTable.rows.item(rowIndex).style.display = 'table-row';
}
}
</script>
這是我的html代碼
<input id="searchTerm" class="form-control" placeholder="Enter text" onkeyup="doSearch()">
<table id="report" class="table">
<thead>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Email</th>
</tr>
</thead>
<tbody>
<tr>
<td>John</td>
<td>Doe</td>
<td>john@example.com</td>
</tr>
<tr>
<td>Mary</td>
<td>Moe</td>
<td>mary@example.com</td>
</tr>
<tr>
<td>July</td>
<td>Dooley</td>
<td>july@example.com</td>
</tr>
</tbody>
</table>
我有另一個問題。 我在html表上添加了一個可擴展行,現在搜索沒有給出所需的輸出。 例如,當我搜索不在html表中的值時,只需刪除第一行並顯示其余行。 這不是正確的輸出。
<table id="report" class="table">
<thead>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Email</th>
<th></th>
</tr>
</thead>
<tbody>
<tr>
<td>John</td>
<td>Doe</td>
<td>john@example.com</td>
<td>
<div class="arrow"><a id="menu-toggle" href="#" ><i class="glyphicon glyphicon-plus-sign"></i></a></div>
</td>
</tr>
<tr><td colspan="4">
<button type="button" class="btnview btn btn-xs btn-warning" >
<span class="glyphicon glyphicon-remove-circle" aria-hidden="true"></span>View
</button>
</td>
</tr>
<tr>
<td>Mary</td>
<td>Moe</td>
<td>mary@example.com</td>
<td>
<div class="arrow"><a id="menu-toggle" href="#" ><i class="glyphicon glyphicon-plus-sign"></i></a></div>
</td>
</tr>
<tr><td colspan="4">
<button type="button" class="btnview btn btn-xs btn-warning" >
<span class="glyphicon glyphicon-remove-circle" aria-hidden="true"></span>View
</button>
</td>
</tr>
<tr>
<td>July</td>
<td>Dooley</td>
<td>july@example.com</td>
<td>
<div class="arrow"><a id="menu-toggle" href="#" ><i class="glyphicon glyphicon-plus-sign"></i></a></div>
</td>
</tr>
<tr><td colspan="4">
<button type="button" class="btnview btn btn-xs btn-warning" >
<span class="glyphicon glyphicon-remove-circle" aria-hidden="true"></span>View
</button>
</td>
</tr>
</tbody>
</table>
集成您的代碼后,羅馬先生。 搜索現在按預期進行。 但是當searchterm輸入為空時,我按退格鍵。 變成這樣
我相信這應該可以回答您的問題。 我只是在調整要搜索的列數:
for (var colIndex = 0; colIndex < (targetTableColCount-1); colIndex++) {
這是一個例子:
http://codepen.io/anon/pen/PNWNmL
更新資料
好的,我不確定這是否是您所需要的正確解決方法,但是我只是注釋掉了導致退格時顯示該按鈕的代碼。 這是我所做的:
<tbody>
<tr>
<td>John</td>
<td>Doe</td>
<td>john@example.com</td>
<td>
<div class="arrow"><a id="menu-toggle" href="#" ><i class="glyphicon glyphicon-plus-sign"></i></a></div>
</td>
</tr>
<tr>
<!-- <td colspan="4">
<button type="button" class="btnview btn btn-xs btn-warning" >
<span class="glyphicon glyphicon-remove-circle" aria-hidden="true"></span>View
</button>
</td> -->
</tr>
<tr>
<td>Mary</td>
<td>Moe</td>
<td>mary@example.com</td>
<td>
<div class="arrow"><a id="menu-toggle" href="#" ><i class="glyphicon glyphicon-plus-sign"></i></a></div>
</td>
</tr>
<tr>
<!-- <td colspan="4">
<button type="button" class="btnview btn btn-xs btn-warning" >
<span class="glyphicon glyphicon-remove-circle" aria-hidden="true"></span>View
</button>
</td> -->
</tr>
<tr>
<td>July</td>
<td>Dooley</td>
<td>july@example.com</td>
<td>
<div class="arrow"><a id="menu-toggle" href="#" ><i class="glyphicon glyphicon-plus-sign"></i></a></div>
</td>
</tr>
<tr>
<!-- <td colspan="4">
<button type="button" class="btnview btn btn-xs btn-warning" >
<span class="glyphicon glyphicon-remove-circle" aria-hidden="true"></span>View
</button>
</td> -->
</tr>
</tbody>
這是一個jsfiddle:
解決方案,其中包括您的其他要求( 表中具有可擴展的行 ):
-替換嵌套的for
循環(通過行列),如下所示:
(您還應該跳過僅包含一個單元格(td)的行)
...
var rowCells = targetTable.rows.item(rowIndex).cells, cellsLen = rowCells.length;
if (cellsLen > 1) {
for (var colIndex = 0; colIndex < 2; colIndex++) {
var cellText = '';
if (targetTable.rows.item(rowIndex).cells.item(colIndex)) {
cellText = rowCells.item(colIndex)[(navigator.appName == 'Microsoft Internet Explorer')? "innerText" : "textContent"];
}
rowData += cellText;
}
}
// Make search case insensitive.
rowData = rowData.toLowerCase().trim();
searchText = searchText.toLowerCase();
//If search term is not found in row data
//then hide the row, else show
if (cellsLen > 1) {
if (searchText && rowData.indexOf(searchText) === -1) {
targetTable.rows.item(rowIndex).style.display = 'none';
} else {
targetTable.rows.item(rowIndex).style.display = 'table-row';
}
}
...
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