在Java中執行curl命令

Question

這是我試圖在Java中執行的curl命令：

curl -XPOST \
   https://login.spredfast.com/v1/oauth/authorize \
   -d response_type="code" \
   -d state="<origState>" \
   --data-urlencode password="<userPassword>" \
   --data-urlencode client_id="<clientId>" \
   --data-urlencode email="<userEmail>" \
   --data-urlencode redirect_uri="<redirectUri>"

這是我上面的java程序：

package jsontocsv;

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.util.Arrays;

public class NoName2 {

  public static void main(String[] args) {
    NoName2 obj = new NoName2();



    String[] command = new String[]
            {
            "curl","-XPOST", "https://login.xyz.com/v1/oauth/authorize",

            "-d", "'response_type=code'",
            "-d", "'state=none'",
            "--data-urlencode","'password=<password>'",
            "--data-urlencode", "'client_id=<client id>'",
            "--data-urlencode", "'email=<email>'",
            "--data-urlencode", "'redirect_uri=https://localhost'",
            };

    String output = obj.executeCommand(command);
    System.out.println(output);
  }

  private String executeCommand(String...command) {
    StringBuffer output = new StringBuffer();

    Process p;
    try {
      p = Runtime.getRuntime().exec(command);

      //p.waitFor();
      BufferedReader reader = new BufferedReader(new InputStreamReader(
          p.getInputStream()));
      System.out.println(reader.readLine()); // value is NULL
      String line = "";
      while ((line = reader.readLine()) != null) {
        System.out.println(line);
        output.append(line + "\n");
      }
    } catch (Exception e) {
      e.printStackTrace();
    }
    return output.toString();
  }
}

但是我得到的輸出不是我期望的。 似乎curl命令的高亮顯示的行似乎沒有在運行：

"--data-urlencode","'password=<password>'",
"--data-urlencode", "'client_id=<client id>'",
"--data-urlencode", "'email=<email>'",
"--data-urlencode", "'redirect_uri=https://localhost'",

我的curl命令及其參數的代碼格式正確嗎？ 任何幫助深表感謝！ 提前致謝！

Answer 1

我強烈建議您為此使用HTTP庫，並避免執行外部程序。 那里有許多用於Java的HTTP庫（用於Java的Rest客戶嗎？ ）。

您一定應該看看Retrofit，在我看來，這非常方便（ http://square.github.io/retrofit/ ）。

您可能還想使用OkHTTP或AsyncHTTPClient。

后者解決您的問題的示例：

AsyncHttpClient asyncHttpClient = new AsyncHttpClient();
BoundRequestBuilder r = asyncHttpClient.preparePost("https://login.xyz.com/v1/oauth/authorize");
r.addParameter("password", "<value>");
r.addParameter("client_id", "<id>");
r.addParameter("email", "<email>");
r.addParameter("redirect_uri", "https://localhost");
Future<Response> f = r.execute();

Response r = f.get();

然后，響應對象提供狀態代碼或HTTP正文。 （ https://asynchttpclient.github.io/async-http-client/apidocs/com/ning/http/client/Response.html ）

編輯：

有點奇怪，是您要發布，但是說使用curl到url編碼您的參數，這在使用HTTP Post時並不常見，也許您可​​以嘗試：

curl -XPOST \
   https://login.spredfast.com/v1/oauth/authorize \
   -d response_type="code" \
   -d state="<origState>" \
   --data 'password="<userPassword>"' \
   --data 'client_id="<clientId>"' \
   --data 'email="<userEmail>"' \
   --data 'redirect_uri="<redirectUri>"'

編輯：完整示例

import com.ning.http.client.AsyncHttpClient;
import com.ning.http.client.Response;

import java.io.IOException;
import java.util.concurrent.ExecutionException;
import java.util.concurrent.Future;

public class Main {

    public static void main(String[] args) throws ExecutionException, InterruptedException, IOException {
        AsyncHttpClient asyncHttpClient = new AsyncHttpClient();
        AsyncHttpClient.BoundRequestBuilder r = asyncHttpClient.preparePost("https://httpbin.org/post");
        r.addFormParam("password", "<value>");
        r.addFormParam("client_id", "<id>");
        r.addFormParam("email", "<email>");
        r.addFormParam("redirect_uri", "https://localhost");
        Future<Response> f = r.execute();

        Response res = f.get();

        System.out.println(res.getStatusCode() + ": " + res.getStatusText());
        System.out.println(res.getResponseBody());
    }

}

輸出：

200: OK
{
  "args": {}, 
  "data": "", 
  "files": {}, 
  "form": {
    "client_id": "<id>", 
    "email": "<email>", 
    "password": "<value>", 
    "redirect_uri": "https://localhost"
  }, 
  "headers": {
    "Accept": "*/*", 
    "Content-Length": "94", 
    "Content-Type": "application/x-www-form-urlencoded", 
    "Host": "httpbin.org", 
    "User-Agent": "AHC/1.0"
  }, 
  "json": null, 
  "origin": "??.??.??.??", 
  "url": "https://httpbin.org/post"
}

您可以使用以下Maven添加AsyncHTTPClient庫（ http://search.maven.org/#artifactdetails%7Ccom.ning%7Casync-http-client%7C1.9.36%7Cjar ）：

<dependency>
    <groupId>com.ning</groupId>
    <artifactId>async-http-client</artifactId>
    <version>1.9.36</version>
</dependency>

通常，只需看看Java的不同HTTP客戶端庫，然后使用您最喜歡的庫即可（我更喜歡前面提到的Retrofit）。