Python變量替換

Question

我有一個腳本，它調用了我要整理的Linux來賓列表。 這是代碼：

#!/usr/bin/python


guests = ['guest1','guest2','guest3','guest*']
def serverCheck(guestList)
    for g in guestList:
        server = AdminControl.completeObjectName('cell=tstenvironment,node=guest1,name=uatenvironment,type=Server,*')
        try:
            status = AdminControl.getAttribute(server, 'state')
            print g + status
        except:
            print "Error %s is down." % g
serverCheck(guests)

問題出在這一行：

server = AdminControl.completeObjectName('cell=Afcutst,node=%s,name=afcuuat1,type=Server,*') % g

我如何使用列表填充節點變量，同時仍然能夠將括號內的信息傳遞給AdminControl函數？

Answer 1

參數字符串本身是%運算符的參數，而不是函數調用的返回值。

server = AdminControl.completeObjectName(
    'cell=Afcutst,node=%s,name=afcuuat1,type=Server,*' % (g,)
)

---

窺探水晶球，Python 3.6將允許您編寫

server = AdminControl.completeObjectName(
    f'cell=Afcutst,node={g},name=afcuuat1,type=Server,*'
)

將變量直接嵌入到特殊格式的字符串文字中。

Answer 2

你可以這樣嘗試嗎

AdminControl.completeObjectName('cell=tstenvironment,node=%s,name=uatenvironment,type=Server,*'%g)

Answer 3

為了提高可讀性，我建議這樣做，並且也使用相同的方式來格式化變量的字符串（在這里我選擇了str.format ）

guests = ['guest1','guest2','guest3','guest*']

def serverCheck(guestList)
    name_tpl = 'cell=tstenvironment,node={},name=uatenvironment,type=Server,*'

    for g in guestList:
        obj_name = name_tpl.format(g)
        server = AdminControl.completeObjectName(obj_name)
        try:
            status = AdminControl.getAttribute(server, 'state')
            print '{}: {}'.format(g, status)
        except:
            print 'Error {} is down'.format(g)

serverCheck(guests)