查詢生成器Codeigniter 3

Question

我這個mysql查詢

SELECT project.title project_title, category.category, project_details.description description, SUM(project_details.quantity) total_quantity, project_details.unit, SUM(project_details.price) total_price, SUM(project_details.jan) total_jan, SUM(project_details.feb) total_feb, SUM(project_details.mar) total_mar, SUM(project_details.apr) total_apr, SUM(project_details.may) total_may, SUM(project_details.jun) total_jun, SUM(project_details.jul) total_jul, SUM(project_details.aug) total_aug, SUM(project_details.sep) total_sep, SUM(project_details.oct) total_oct, SUM(project_details.nov) total_nov, SUM(project_details.dec) total_dec
FROM project_details
JOIN project ON project_details.project_id = project.id
JOIN category ON project_details.category_id = category.id
JOIN user ON project.user_id = user.id
RIGHT JOIN office ON user.office_id = office.id
WHERE EXISTS 
    (
        SELECT t1.id id1, t2.id id2, t3.id id3, t4.id id4, t5.id id5
        FROM user t1
        LEFT JOIN user t2 ON t2.reports_to = t1.id
        LEFT JOIN user t3 ON t3.reports_to = t2.id
        LEFT JOIN user t4 ON t4.reports_to = t3.id
        LEFT JOIN user t5 ON t5.reports_to = t4.id
        WHERE t1.id = 81
    )
    AND project.approval_status = 22 AND project.reason_for_rejection IS NULL
GROUP BY project.id, project_details.description
ORDER BY project_details.category_id

但是，我在Codeigniter 3.0中找不到任何文檔，在這里可以找到WHERE EXISTS 。 我已經檢查了這個https://www.codeigniter.com/userguide3/database/query_builder.html，但是沒有。

這是我現在的代碼

$this->db->select('project.title project_title, category.category, project_details.description description, SUM(project_details.quantity) total_quantity, project_details.unit, SUM(project_details.price) total_price, SUM(project_details.jan) total_jan, SUM(project_details.feb) total_feb, SUM(project_details.mar) total_mar, SUM(project_details.apr) total_apr, SUM(project_details.may) total_may, SUM(project_details.jun) total_jun, SUM(project_details.jul) total_jul, SUM(project_details.aug) total_aug, SUM(project_details.sep) total_sep, SUM(project_details.oct) total_oct, SUM(project_details.nov) total_nov, SUM(project_details.dec) total_dec');
$this->db->from('project_details');
$this->db->join('project', 'project_details.project_id = project.id');
$this->db->join('category', 'project_details.category_id = category.id');
$this->db->join('user', 'project.user_id = user.id');
$this->db->join('office', 'user.office_id = office.id', 'right');
// THIS IS WHERE I WANT TO PUT THE WHERE EXISTS
$this->db->where('project.approval_status', $user_id);
$this->db->where('project.reason_for_rejection IS NULL', NULL, TRUE);
$this->db->group_by('project.id');
$this->db->group_by('project_details.description');
$this->db->order_by('project_details.category_id');
$query = $this->db->get();
return $query->result();

有人可以幫我如何在codeigniter中實現嗎？ 先進的謝謝。

Answer 1

當您有非常大的查詢時，或者在查詢構建器中沒有is內置函數供您使用時，您始終可以使用：

$query = $this->db->query('your large query');

您還應該注意注射劑，因此您也應該閱讀這篇文章

這很好地解釋了如何對SQL注入使用$this->db->query方法。

希望這可以幫助