如何獲得每天的總小時數

Question

我有一種情況，我需要計算每天每套的總工作時間。 但是我堅持了很多天。 我嘗試獲得如下輸出：

Day        Clock In  Clock Out  Total Hours(Hr)   Total Hours Per Day(Hr)
Monday     08:00     09:00      1.00                                     
           10:00     12:00      2.00          
           13:00     14:30      1.50              4.50
Tuesday    08:30     10:00      1.50
           15:00     17:50      2.83              4.33
Wednesday  08:00     17:00      9.00              9.00

                                     Total       17.83

到目前為止，我已經嘗試編寫代碼並做出了一些努力。 請幫助我。 會非常感激。

for($days=0;$days<3;$days++) { //get how many days

$clocked_records_each_day = count($get_attendance_records); //get attendance                 clock sets

for($records=0; $records<$clocked_records_each_day; $records++) {
$total_hour_per_set = $clocked_records_each_day[$records]['total_hour'];
$total_hour_per_day = ??;
$total_hour_overall = ??;
//stuck until here
//get the output and display
}

}

Answer 1

基本上：

/* Init grand total:  */
$total_hour_overall = 0;

for($days=0;$days<3;$days++) { //get how many days

    /* Init day subtotal at each for loop: */
    $total_hour_per_day = 0;

    $clocked_records_each_day = count($get_attendance_records); //get attendance                 clock sets

    for($records=0; $records<$clocked_records_each_day; $records++) {
        $total_hour_per_set = $clocked_records_each_day[$records]['total_hour'];

        /* Increment day subtotal and grand total: */
        $total_hour_per_day += $clocked_records_each_day[$records]['total_hour'];
        $total_hour_overall += $clocked_records_each_day[$records]['total_hour'];

        /* Echo set total inside records for:  */
        echo $total_hour_per_set;
    }

    /* Echo day subtotal inside days for:  */
    echo $total_hour_per_day;
}

/* Echo grand total outside for loop:  */
echo $total_hour_overall;

Answer 2

您需要分兩部分進行操作，首先將其總和，然后顯示出來。

for($records=0; $records<$clocked_records_each_day; $records++) {
  $total_hour_per_set = $clocked_records_each_day[$records]['total_hour'];
  $total_hour_per_day[$clocked_records_each_day[$records]['day'][] =  $total_hour_per_set
  $total_hour_overall+= $total_hour_per_set;
}

因此，現在您擁有了所需的所有數據。

每天您都可以展示

for($records=0; $records<$clocked_records_each_day; $records++) {
  Display( $total_hour_per_set = $clocked_records_each_day[$records]['total_hour']);
  Display( array_sum( $total_hour_per_day[$clocked_records_each_day[$records]['day'] ) );
  Display( $total_hour_overall+= $total_hour_per_set );
}

假定您具有Display（...）函數。