PHP搜索字符串逗號分隔並獲取匹配的元素

Question

我有一個問題，是否有人可以幫助我解決這個問題。 我有一個用逗號分隔的字符串，我想找到一個部分匹配的項目：

$search = "PrintOrder";
$string = "IDperson, Inscription, GenomaPrintOrder, GenomaPrintView";

由於過濾器，我只需要從部分匹配中獲取完整字符串：

$result = "GenomaPrintOrder";

Answer 1

使用preg_match_all您可以做到這一點。

郵遞區號

<?php
  $subject = "IDperson, Inscription, GenomaPrintOrder, GenomaPrintView, NewPrintOrder";
  $pattern = '/\b([^,]*PrintOrder[^,]*)\b/';
  preg_match_all($pattern, $subject, $matches, PREG_SET_ORDER);
  foreach ($matches as $val) {
      echo "Matched: " . $val[1]. "\n";
  }
?>

輸出量

Matched: GenomaPrintOrder
Matched: NewPrintOrder

Ideone演示

Answer 2

$search = "PrintOrder";
$string = "IDperson, Inscription, GenomaPrintOrder, GenomaPrintView";
$result = array();
$tmp = explode(",", $string);
foreach($tmp as $entrie){
    if(strpos($entrie, $string) !== false)
        $result[] = trim($entrie);
}

這將為您提供一個數組，其中包含與您的搜索字符串匹配的所有字符串。

Answer 3

您可以使用正則表達式獲取結果：

$search = "PrintOrder";
$string = "IDperson, Inscription, GenomaPrintOrder, GenomaPrintView";

$regex = '/([^,]*' . preg_quote($search, '/') . '[^,]*)/';

preg_match($regex, $string, $match);

$result = trim($match[1]); // $result == 'GenomaPrintOrder'

Answer 4

$search = "PrintOrder";
$string = "IDperson, Inscription, GenomaPrintOrder, GenomaPrintView";


$array = explode(" ", $string);
echo array_filter($array, function($var) use ($search) { return preg_match("/\b$searchword\b/i", $var); });

Answer 5

由於已經有很多不同的答案，因此這是另一個：

$result = preg_grep("/$search/", explode(", ", $string));
print_r($result);