python-函數不在while循環中調用

Question

noprob=["nothing","none","no damage"]

while True:
    q1=input("input your answer:")
    answer=q1.split(' ')`


    if any(a in answer for a in noprob):
        function()#wont call this
        break
    else:
        print("else statement")
        continue

def function():
    print("code now works")

我的代碼不會在應該調用該函數時調用該函數。 此代碼應識別用戶輸入並輸出必要的操作。

新的完整代碼：添加了 elif 語句，我認為這是代碼的問題

`noprob=["nothing","none","no damage"]
something=["something","yes"]`

def function():
    print("code now works")`

def something():
    print("something, code works")
while True:
    q1=input("input your answer:")
    answer=q1.split(' ')`


    if any(a in answer for a in noprob):
        function()#wont call this
        break
    elif any(a in answer for a in something):
        something()
        break
    else:
        print("else statement")
        continue

Answer 1

Python 從上到下執行代碼。 所以如果你之前沒有聲明它的定義，你將無法執行function 。 將函數移動到while循環之前。

noprob=["nothing","none","no damage"]

def function():
    print("code now works")

while True:
    q1=input("input your answer:")
    answer=q1.split(' ')


    if any(a in answer for a in noprob):
        function()#wont call this
        break
    else:
        print("else statement")
        continue

Answer 2

您的問題是，您的列表和函數都命名為something 。 重命名一個並相應地更改您的代碼。

something=["something","yes"]

def something(): #this one shadows your list and needs to be renamed
    print("something, code works")

對於生成器， Python 3.5