來自不同表的SQL JOIN行具有相同的值

Question

所以我有這張桌子

  code  |  name
  -----------------
  1     |  abc
  2     |  asd
  3     |  aws

然后我有這個新表用於交易

  code  | new_code
  ---------------------
  1     | 2
  2     | 3

我想獲得如下所示的視圖：

  code  |  name  |  new_code  |  name  |
  ---------------------------------------
  1     | abc    |  2         |  asd   |
  2     | asd    |  3         |  aws   |

我應該對此視圖使用哪種查詢。 謝謝

Answer 1

SELECT t.code, t.name, n.new_code, nt.name
FROM   this_table t
INNER JOIN new_table n   ON t.code = n.code
INNER JOIN this_table nt ON n.new_code = nt.code

Answer 2

您的案例的架構。

        SELECT * INTO #TAB1 FROM (
        SELECT 1 CODE ,'ABC' NAME
        UNION ALL
        SELECT 2,'ASD'
        UNION ALL
        SELECT 3,'AWS'
        ) AS A

        SELECT * INTO #TAB2 FROM (
        SELECT  1 AS CODE, 2 AS NEW_CODE
        UNION ALL
        SELECT 2,3
        )AS A

而下一個是解決方案

        SELECT T1.*, T2.NEW_CODE, T3.NAME FROM 
        #TAB1 T1 
        INNER JOIN #TAB2 T2 ON T1.CODE = T2.CODE
        INNER JOIN #TAB1 T3 ON T2.NEW_CODE = T3.Code

Answer 3

您也可以使用這種方式

SELECT
    nt.code,
    (SELECT name FROM first_table where code=nt.code) AS name,
    nt.new_code,
    (SELECT name FROM first_table where code=nt.new_code) AS name
new_table nt

Answer 4

SELECT table1.code, table1.name, table2.new_code, table2.name
FROM   table1
JOIN table2 ON table1.code = table2.code;