[英]Checking for inconsistent values within groups
考慮下表
document_id group_id level
--------------------------------
1 1 1
2 1 1
3 2 3
4 2 3
5 2 2
6 3 1
7 4 6
8 4 6
9 4 6
10 5 2
11 5 1
我想檢查level
的文件之一內group_id
是一致的,如果沒有,顯示這些群體。 因此,對於上面的示例,輸出必須為:
document_id group_id level
--------------------------------
3 2 3
4 2 3
5 2 2
10 5 2
11 5 1
我該如何實現? 任何幫助,將不勝感激。
使用EXISTS
查找相同group_id的級別值不一致的行:
select document_id, group_id, level
from tablename t1
where exists (select 1 from tablename t2
where t2.group_id = t1.group_id
and t2.level <> t1.level)
這是它的執行方式:
SQL>create table t (document_id int, group_id int, level int);
SQL>insert into t values( 1, 1, 1);
SQL>insert into t values( 2, 1, 1);
SQL>insert into t values( 3, 2, 3);
SQL>insert into t values( 4, 2, 3);
SQL>insert into t values( 5, 2, 2);
SQL>insert into t values( 6, 3, 1);
SQL>insert into t values( 7, 4, 6);
SQL>insert into t values( 8, 4, 6);
SQL>insert into t values( 9, 4, 6);
SQL>insert into t values(10, 5, 2);
SQL>insert into t values(11, 5, 1);
SQL>select document_id, group_id, level
SQL&from t t1
SQL&where exists (select 1 from t t2
SQL& where t2.group_id = t1.group_id
SQL& and t2.level <> t1.level);
document_id group_id level
=========== =========== ===========
3 2 3
4 2 3
5 2 2
10 5 2
11 5 1
5 rows found
結果與所指定的相同。
修改了jarlh的答案,以使查詢結果與OP的期望輸出匹配:
使用EXISTS查找這些行,其中同一組也具有另一個級別:
select document_id, group_id, level
from tablename t1
where exists (select 1 from tablename t2
where t2.level <> t1.level
and t2.group_id = t1.group_id)
作為一種替代exists
,你可以使用窗口功能:甲
select document_id, group_id, level
from (select t.*, min(level) over (partition by group_id) as minlevel,
max(level) over (partition by group_id) as maxlevel
from t
) t
where minlevel <> maxlevel;
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