javascript音頻語法可能不正確？

Question

它不會播放聲音。 我已經看到了JavaScript音頻的不同語法公式，但是現在我不確定什么是對的還是什么錯了。 我猜問題出在新的音頻位，因為我不確定這是否正確。 謝謝您的幫助。

var greenSound = new Audio('<https://s3.amazonaws.com/freecodecamp/simonSound1.mp3>');
    var redSound = new Audio('<https://s3.amazonaws.com/freecodecamp/simonSound2.mp3>');
    var blueSound = new Audio('<https://s3.amazonaws.com/freecodecamp/simonSound3.mp3>');
    var yellowSound = new Audio('<https://s3.amazonaws.com/freecodecamp/simonSound4.mp3>');
    var sounds = [greenSound, redSound, blueSound, yellowSound];
    var soundNums = [];


num = Math.floor(4*Math.random());
                    simon.push(moves[num]);
                    soundNums.push(num);
                    for(var i = 0; i < simon.length; i++)
                        {
                            $(simon[i]).fadeOut(200).fadeIn(200);
                            (sounds[soundNums[i]]).play();
                        }

Answer 1

一切正常，您在URL中有語法問題。

由此：

var mp3 = new Audio('<https://s3.amazonaws.com/freecodecamp/simonSound1.mp3>');

對此：

var mp3 = new Audio('https://s3.amazonaws.com/freecodecamp/simonSound1.mp3');