如何在C ++中打印/檢查向量的值

Question

我只想在代碼運行時檢查變量的值（就像您在Matlab中只需鍵入變量名即可）。 我插入了一行代碼cout << img_names; 在示例開源代碼中，但no operator "<<" matches these operands Visual Studio錯誤列表no operator "<<" matches these operands 。 但是，我發現示例代碼的其他部分都很好地使用了cout。 以下是插入cout的示例代碼的開始部分：

#include <iostream>
#include <fstream>
#include <string>
#include "opencv2/opencv_modules.hpp"
#include <opencv2/core/utility.hpp>
#include "opencv2/imgcodecs.hpp"
#include "opencv2/highgui.hpp"
#include "opencv2/stitching/detail/autocalib.hpp"
#include "opencv2/stitching/detail/blenders.hpp"
#include "opencv2/stitching/detail/timelapsers.hpp"
#include "opencv2/stitching/detail/camera.hpp"
#include "opencv2/stitching/detail/exposure_compensate.hpp"
#include "opencv2/stitching/detail/matchers.hpp"
#include "opencv2/stitching/detail/motion_estimators.hpp"
#include "opencv2/stitching/detail/seam_finders.hpp"
#include "opencv2/stitching/detail/util.hpp"
#include "opencv2/stitching/detail/warpers.hpp"
#include "opencv2/stitching/warpers.hpp"

using namespace std;
using namespace cv;
using namespace cv::detail;

static void printUsage(){ ... }

// Default command line args
vector<String> img_names;
bool preview = false;
bool try_cuda = false;
double work_megapix = 0.6;
double seam_megapix = 0.1;
double compose_megapix = -1;
float conf_thresh = 1.f;
string features_type = "surf";
string ba_cost_func = "ray";
string ba_refine_mask = "xxxxx";
bool do_wave_correct = true;
WaveCorrectKind wave_correct = detail::WAVE_CORRECT_HORIZ;
bool save_graph = false;
std::string save_graph_to;
string warp_type = "spherical";
int expos_comp_type = ExposureCompensator::GAIN_BLOCKS;
float match_conf = 0.3f;
string seam_find_type = "gc_color";
int blend_type = Blender::MULTI_BAND;
int timelapse_type = Timelapser::AS_IS;
float blend_strength = 5;
string result_name = "result.jpg";
bool timelapse = false;
int range_width = -1;

static int parseCmdArgs(int argc, char** argv){ ... }

int main(int argc, char* argv[])
{
#if ENABLE_LOG
    int64 app_start_time = getTickCount();
#endif

#if 0
    cv::setBreakOnError(true);
#endif

    int retval = parseCmdArgs(argc, argv);
    cout << img_names;
    if (retval)
        return retval;

much more code continues...

如何正確使用cout來獲取變量值，或者有更簡單的方法嗎？

Answer 1

沒有為std::vector定義operator << ，因為沒有標准的方法可以打印該類型。 您可以像這樣實現自己的

std::ostream& operator<< (std::ostream& out, const std::vector<String>& vec)
{
    for (int i = 0; i < vec.size(); i++)
        out << vec[i] << " "; // or whatever formatting you like

    return out;
}