[英]Return exception from JAX-RS Rest Service as JSON
從REST服務拋出的異常是否以某種方式作為JSON返回? 我有一個JAX-RS Rest Service,我想實現這一目標。 當我現在扔它時,它被映射到HTML響應,這不是我想要的。 據我了解,ExceptionMapper還將其映射到HTML嗎? 是否有其他替代方法或庫允許以JSON格式返回異常?
它將以JSON響應。
@Provider
@Singleton
public class ExceptionMapperProvider implements ExceptionMapper<Exception>
{
@Override
public Response toResponse(final Exception exception)
{
return Response.status(HttpStatusCodes.STATUS_CODE_SERVER_ERROR).entity(new BasicResponse(InternalStatus.UNHANDLED_EXCEPTION, exception.getMessage())).type(MediaType.APPLICATION_JSON).build();
}
}
@XmlRootElement
public class BasicResponse {
public String internalStatus;
public String message;
public BasicResponse() {}
public BasicResponse(String internalStatus, String message){
this.internalStatus = internalStatus;
this.message = message;
}
}
您可以創建自定義異常,它需要JSON請求和響應
@POST
@Path("/betRequest")
@Consumes({ "application/json", "application/x-www-form-urlencoded" })
@Produces({ "application/json", "application/x-www-form-urlencoded" })
public Response getBetRequest(String betRequestParams, @Context HttpServletRequest request)
{
BetResponseDetails betResponseDetails = new BetResponseDetails();
try{
//you code here
}
catch (JSONException ex)
{
ex.printStackTrace();
betResponseDetails.setResponseCode("9002");//your custom error code
betResponseDetails.setResponseStatus("Bad Request");//custom status
betResponseDetails.setResponseMessage("The request body contained invalid JSON");//custom error massage
return Response.status(200).entity(betResponseDetails).build();
}
}
創建一個POJO BetResponseDetails
public class BetResponseDetails {
private String ResponseStatus;
private String ResponseCode;
private String ResponseMessage;
// getter/setter
.......
}
捕獲異常,然后以標准化格式構建響應對象,例如
error: {
code: 'XXX',
status: HTTPStatus,
message: 'my error message'
}
並將其作為帶有錯誤狀態的響應發送(來自Response.Status,通常為4xx或5xx)
在具有狀態和數據的結構中獲取響應數據,如果狀態為錯誤,則顯示正確的消息。 你可以這樣嘗試
{
"status": "error",
"data": {
"message": "information of error message"
}
}
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