選擇語句中的選擇語句

Question

我有以下選擇語句，返回的正是我想要的：

DECLARE @result varchar(max) = ''

SELECT @result += (result.Fullname + '<br/>') 
FROM (SELECT DISTINCT Fullname
FROM Providers 
WHERE Status='A') as result

select substring(@result, 0, len(@result) - 4)

唯一的問題是，我希望此查詢的輸出顯示為較大選擇語句中的列條目。

例如。

SELECT      
    Column AS [AColumnName],

    SELECT @result += (result.Fullname + '<br/>') 
    FROM (SELECT DISTINCT Fullname
    FROM Providers 
    WHERE Status='A') as result

    select substring(@result, 0, len(@result) - 4) as [LenderList]
FROM
 Table

但我目前遇到錯誤：關鍵字“ SELECT”附近的語法不正確。 指向第4行的錯誤

有任何想法嗎？

Answer 1

您需要在SQL Server中聚合字符串串聯。 子查詢上已經有很多答案，但是為您省去了麻煩：

SELECT Column AS [AColumnName],
       STUFF((SELECT DISTINCT '<br/>' + Fullname
              FROM Providers 
              WHERE Status = 'A'
              FOR XML PATH (''), TYPE
             ).value('.', 'varchar(max)'
                    ), 1, 5, ''
            ) as result
FROM Table;

類型的使用很重要，因為您的字符串具有特殊的XML字符。

Answer 2

您可以簡單地在2條語句中運行它嗎？

SELECT @result += (result.Fullname + '<br/>') 
FROM (SELECT DISTINCT Fullname
     FROM Providers 
     WHERE Status='A') as result

SELECT      
    Column AS [AColumnName],
    substring(@result, 0, len(@result) - 4)
FROM Table

Answer 3

哪個數據庫？ 如果可以用於xml，則類似...

select substring(a.innards, 0, len(a.innards) - 4) as [LenderList]
from 
(
    SELECT innards = STUFF(
        (SELECT DISTINCT Fullname + '</br>'
        FROM Providers
        WHERE [Status] = 'A'
        FOR XML PATH(''), TYPE).value('.[1]', 'nvarchar(max)')
        , 1
        , 0
        , '')
) a