NSURL nil由於空格

Question

端點不關心URL中是否包含空格，但NSURL似乎可以。

我得到的NSURL *url = [NSURL URLWithString:string]; nil NSURL *url = [NSURL URLWithString:string]; 每次：

NSString *string = [NSString stringWithFormat:@"http://endpoint.com/search?one=%@&two=%@", textField1.text, textField2.text];
NSURL *url = [NSURL URLWithString:string];
NSString *urlAbsolute = [url absoluteString];
[theManager GET:urlAbsolute parameters:nil progress:nil success:^(NSURLSessionTask * _Nonnull task, id  _Nullable responseObject) {

我想將空格傳遞到端點中，因為我想從端點中獲取空格。 （即傳入“星球大戰”，因此如果我從字符串中刪除了空格，我將得到“星球大戰”而不是“星球大戰”）。

有任何想法嗎？

Answer 1

將字符串編碼與允許的字符一起使用請找到以下代碼。

NSString *string = [NSString stringWithFormat:@"http://endpoint.com/search?one=%@&two=%@", textField1.text, textField2.text];
NSURL *url = [NSURL URLWithString:[string stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]]];

Answer 2

試試這個代碼：

NSString *firstArgument = [self.textField1.text stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]];
NSString *secondArgument = [self.textField2.text stringByAddingPercentEncodingWithAllowedCharacters:[NSCharacterSet URLHostAllowedCharacterSet]];

NSString *string = [NSString stringWithFormat:@"http://endpoint.com/search?one=%@&two=%@", firstArgument, secondArgument];
NSURL *url = [NSURL URLWithString:string];
NSString *urlAbsolute = [url absoluteString];