[英]How to pivot and count a MySQL table like this?
我有下表。 我該如何調整它並計算每個問題的答復? 第二張表是我想要的結果。
嘗試此操作,您應該將@table替換為表名。
select
'Q1' as Question,
sum(if(Q1='yes', num, 0)) as 'yes',
sum(if(Q1='no', num, 0)) as 'no',
sum(if(Q1='could be', num, 0)) as 'could be'
from (select Q1, count(Q1) as num from @table group by Q1) Q1
union
select
'Q2' as Question,
sum(if(Q2='yes', num, 0)) as 'yes',
sum(if(Q2='no', num, 0)) as 'no',
sum(if(Q2='could be', num, 0)) as 'could be'
from (select Q2, count(Q2) as num from @table group by Q2) Q2
union
select
'Q3' as Question,
sum(if(Q3='yes', num, 0)) as 'yes',
sum(if(Q3='no', num, 0)) as 'no',
sum(if(Q3='could be', num, 0)) as 'could be'
from (select Q3, count(Q3) as num from @table group by Q3) Q3
union
select
'Q4' as Question,
sum(if(Q4='yes', num, 0)) as 'yes',
sum(if(Q4='no', num, 0)) as 'no',
sum(if(Q4='could be', num, 0)) as 'could be'
from (select Q4, count(Q4) as num from @table group by Q4) Q4
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