[英]PHP: using class name as variable name
我有一個功能為:
public function controller_instance($controller_name)
{
$controller = Router::getRequestedController();
return $controller instanceof $controller_name;
}
我將函數稱為controller_instance('IndexController')
。
這總是返回false,因為變量$controller_name
包含字符串IndexController
。
我該如何進行這項工作?
只需從該控制器字符串創建新類
return $controller instanceof (new $controller_name());
您是否需要實例或布爾值?
在包含方法controller_instance的同一類中創建一個數組屬性,並存儲所有實例
private $controllers = array();
public function controller_instance($controller_name)
{
if (isset($this->controllers[$controller_name])) {
return $this->controllers[$controller_name];
}
return $this->controllers[$controller_name] = new $controller_name();
}
示例2:使用ReflectionClass和參數
private $controllers = array();
public function controller_instance($controller_name, Array $args = array())
{
if (isset($this->controllers[$controller_name])) {
return $this->controllers[$controller_name];
}
$class = new ReflectionClass($controller_name);
$instance = $class->newInstanceArgs($args);
return $this->controllers[$controller_name] = $instance;
}
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