Javascript：如何迭代對象[鍵：值]但跳過一些鍵（[最快的方法]）
[英]Javascript: How to Iterate Object [Key: value] but skip some keys ([fastest way possible])
問題描述
如果給出類似以下的腳本：
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Test DOC</title>
<script type="text/javascript" src="../nt_scr/jq_1.9.js"></script>
<script type="text/javascript">
var mainObj = { 0: { "fruitName":"Lemon",
"fruitColor":"green",
"fruitTaste":"bad"},
1: { "fruitName":"Mango",
"fruitColor":"Yellow",
"fruitTaste":"Yammy"},
2: {
"fruitName":"Banana",
"fruitColor":"Yellow",
"fruitTaste":"Yammy"},
"skip_these":
{
"team1":"Liverpool",
"team2":"Manchester United"
}
}
var collect_data = $.parseJSON(JSON.stringify(mainObj)),
getFruitNames=[],getFruitColors=[], getFruitTastes=[];
$.each( collect_data,function(index,val){
//console.log(val); //Un-comment this console.log to see the contents of 'val'
//----->Here is the Challenge:,---------\\\
if(/*How do you SKIP if val is something like */ "val.team1" || "val.team2"){
getFruitNames.push(val.fruitName);
getFruitColors.push(val.fruitColor);
getFruitTastes.push(val.fruitTaste);
//This works well so long as we have not yet reached the "skip_these":
//Once there, it reports an error because there is no "skip_these".fruitName or "skip_these".fruitColor
}
console.log( getFruitNames[index])// Run a test out put :: NOTICE the "Undefined" in the Console. How to avoid that?
//To see well, Comment the previous console.log <<the one on top>>
})
</script>
</head>
<body>
</body>
</html>
我有時以前做過，但是不知何故，我的大腦現在一片空白...。 （請使用您的jQuery運行）
2 個解決方案
解決方案1
1 2016-04-14 11:06:39
（不是jquery-香草）迭代屬性並跳過特定鍵：（未測試語法，但應該可以）
var skipped = ['keySkipped'];
for (var someProperty in someObject) {
if (someObject.hasOwnProperty(someProperty) && skipped.indexOf(someObject[someProperty] === -1)) {
// do stuff
}
}
說明：迭代屬性，並且屬性是否確實包含在對象中，但不包含在skiped執行任何操作
解決方案2
1 已采納 2016-04-14 11:27:34
正如JQuery文檔所述 ，
返回非false與for循環中的continue語句相同； 它將立即跳至下一個迭代。
因此，按照您的示例，可以使用以下內容跳過具有不需要的屬性的對象：
的JavaScript
$.each( collect_data,function(index,val){
//console.log(val); //Un-comment this console.log to see the contents of 'val'
//----->Here is the Challenge:,---------\\\
if(val.team1 || val.team2){
return true;
}
getFruitNames.push(val.fruitName);
getFruitColors.push(val.fruitColor);
getFruitTastes.push(val.fruitTaste);
//This works well so long as we have not yet reached the "skip_these":
//Once there, it reports an error because there is no "skip_these".fruitName or "skip_these".fruitColor
console.log( getFruitNames[index])//No "Undefined"
})
在Javascript中迭代對象屬性的最快方法是什么？
[英]What's the fastest way to iterate over an object's properties in Javascript?
如何在javascript中迭代數組中對象的鍵值對
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用鍵“減少”嵌套數組到 object 的最快方法 + 用鍵查找的最快方法
[英]Fastest way to “reduce” nested array to object with keys + fastest way to find by key
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