[英]mysqli_fetch_assoc not work
為什么第二次嘗試時第一行沒有顯示? 在屏幕截圖中,第一次回顯時突出顯示第一行。
[![enter image description here][1]][1]/*=================================================================================================================
mysqli_fetch_assoc - returns data in an associative array
mysqli_fetch_row - returns data in a numeric array
mysqli_fetch_array - returns data in both an associative and a numeric array
*/
$query2 = "SELECT * FROM User";
//$result3 = mysqli_query ( $con, $query2) or die ("Couldn't execute SELECT query");
$result3 = mysqli_query ( $con, $query2) or die (mysqli_error($con));
$row = mysqli_fetch_assoc($result3); //returns an array called $row with column names as keys. Get one row of data
//If you need more than one row of data, use the function in a loop
echo $row['Title'] ." - ". $row['FName'] ." - ". $row['LName']; //one row of data. It is fine when checking a password
//extract function - splits the array into variables that have same name as the key
extract($row);
echo "<hr>".$FName; //variable having same name as the key, also identical to column name
echo "<br>Number of rows in the User table: ".mysqli_num_rows($result3);
echo "<table>";
echo "<th>User Id</th> <th>Title</th> <th>First Name</th> <th>Last Name</th> <th>Email</th>";
while( $row = mysqli_fetch_assoc($result3) ){
extract($row);
echo "<tr>";
echo "<td>".$UserId."</td>" . "<td>".$Title."</td>" . "<td>".$FName."</td>" . "<td>".$LName."</td>" . "<td>".$Email."</td>" ;
echo "</tr>";
}
echo "</table>";
echo "<hr>My connection to the MySQL database";
$row = mysqli_fetch_assoc($result3);
因為當您在循環之前執行此操作時,會將指針移到下一行,因此循環從第二行開始。
在循環之前,您可以將指針重置為第一行
mysqli_data_seek($result3,0);
因為,您兩次執行mysqli_fetch_assoc,而沒有重新設置指針。 Hanky Panky說的沒錯。
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