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[英]What regular expression pattern in the url.py do you need to match string 'title' of an object in python/django
[英]django1.8 to have regular expression for url in url.py
我正在嘗試將當前網址發送到我的視圖,以便將其重定向回我從其開始的原始頁面
我正在發送2個參數“ pk”,這是我用於操作的密鑰號,而“ uri”這是我當前的網址
我的url.py下面的行我不知道應該如何設置
url(r'^subcategory/new/(?P<pk>\d+)/(<uri>\s+)/$',item.views.subcategory_new, name="subcategory_new"),
我收到錯誤消息
Reverse for 'subcategory_new' with arguments '()' and keyword arguments '{u'pk': 2, u'uri': 'http://127.0.0.1:8000/item/category/list/?name=M_Textile&keywords=&author=&creation_time='}' not found. 1 pattern(s) tried: ['item/subcategory/new/(?P<pk>\\d+)/(<uri>\\s+)/$']
網址正則表達式中我做錯了什么?
在我其余的代碼下面
我的template.html中的鏈接
<a href="{% url 'subcategory_new' pk=category.id uri=request.build_absolute_uri %}">Add SubCategory</a>
最后是我的view.py
@login_required
def subcategory_new(request,pk,uri):
category = get_object_or_404(Category, pk=pk)
if request.method == "POST":
form = SubCategoryForm(request.POST)
if form.is_valid():
subcategory = form.save(commit=False)
#contact.author = request.user
subcategory.creation_time = timezone.now()
subcategory.category = category
subcategory.save()
return redirect(uri)
else:
form = SubCategoryForm()
return render(request, 'item/subcategory_edit.html', {'form': form, 'category':category })
您缺少uri
的命名捕獲組:
url(r'^subcategory/new/(?P<pk>\d+)/(?P<uri>\S+)/$',item.views.subcategory_new, name="subcategory_new"),
而且,我也用\\S+
替換了\\s+
,因為我懷疑您實際上是想捕獲一個或多個空格字符。
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