[英]Clean way to query complex JSON in Postgresql
我在PostgreSQL 9.5數據庫中的JSONB字段中存儲了JSON數據。
有沒有一種方法可以使子對象列成為子對象而又不知道哪一列是子對象?
有問題的JSON示例:
{
"a":1,
"b":[1,2,3],
"c":"bar",
"d":{
"key1":"value1",
"key2":"value2"
}
}
我可以使用以下代碼從JSON對象獲取所有鍵。
SELECT * FROM json_object_keys('{"a":1,"b":[1,2,3],"c":"bar", "d":{"key1":"value1", "key2":"value2"}}')
那時我可以使用json_to_record(),但我想將列拆分為自己的單獨字段。
select * from json_to_record('{"a":1,"b":[1,2,3],"c":"bar", "d":{"key1":"value1", "key2":"value2"}}') as x(a int, b text, c text, d text)
讓我
a| b | c | d
1| [1,2,3] | bar | {"key1":"value1", "key2":"value2"}
有沒有辦法最好在單個查詢中找回類似的東西?
--------------------------------------------------------------------
a| b | c | d | key1 | key2
1| [1,2,3] | bar | {"key1":"value1", "key2":"value2"} |value1 |value2
WITH t(v) AS ( VALUES
('{
"a":1,
"b":[1,2,3],
"c":"bar",
"d":{
"key1":"value1",
"key2":"value2"
}
}'::JSONB)
)
SELECT x1.*,x2.* FROM t,
jsonb_to_record(v) as x1(a int,b text,c text,d jsonb),
jsonb_to_record(v->'d') as x2(key1 text,key2 text);
結果:
a | b | c | d | key1 | key2
---+-----------+-----+--------------------------------------+--------+--------
1 | [1, 2, 3] | bar | {"key1": "value1", "key2": "value2"} | value1 | value2
(1 row)
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.