避免打印相同的輸出

Question

我正在制作一個故障排除程序，該程序將要求用戶提供輸入，搜索一些列表以查找問題並提供解決方案。

f=open('problem.txt')
lines=f.readlines()

problem1 = ["cracked", "phone", "screen", "dropped"]
problem2 = ["charging", "port", "phone"]
problem3 = ["slow", "phone", "freeze"]

problem_input = input ("What is your problem? ")
list_split = (problem_input.split( ))

for i in problem1:
    if i in list_split:
        print (lines[0])


for i in problem2:
    if i in list_split:
        print (lines[1])    

但是，如果我輸入"my phone is cracked" ，則輸出將被打印兩次。 我如何只打印一次？

Answer 1

您正在遍歷問題案例列表，並且輸入匹配兩次。 匹配是"phone"和"cracked" 。 為了防止這種情況，請在第一個比賽中停下：

for i in problem1:
    if i in list_split:
        print (lines[0])
        break

break關鍵字將退出循環。

Answer 2

您正在遍歷“問題”列表，並獲得針對您狀況的多個匹配項。

您可以通過將其轉化為函數來return匹配的問題：

f=open('problem.txt')
lines=f.readlines()

problem1 = ["cracked", "screen", "dropped"]
problem2 = ["charging", "port"]
problem3 = ["slow", "freeze"]
problems = [problem1, problem2, problem3]

def troubleshoot():
    problem_input = input("What is your problem? ")
    list_split = (problem_input.split())
    for idx, problem in enumerate(problems, 1):
        if any(i in problem for i in list_split):
            return "problem{}".format(idx)
            # or return lines[0]

它將如下運行：

>>> troubleshoot()
What is your problem? my phone is slow and freezing up
'problem3'
>>> troubleshoot()
What is your problem? my phone is not charging
'problem2'
>>> 
>>> troubleshoot()
What is your problem? my phone dropped and the screen is cracked
'problem1'

另外，如果沒有理由在每個problem列表中都包含"phone" ，則最好在此處使用dict ：

problems = {'cracked':1, 'screen':1, 'dropped':1,
            'charging':2, 'port':2,
            'slow':3, 'freeze':3}

user_problems = {problems[i] for i in problem_input.split()}

注意：我從這兩個位置都刪除了"phone" ，因為它與每個列表都匹配