[英]Get data and sort from MySQL two tables
我有table_1
和table_2
,它們的結構相同,但是數據不同。 需要以create_date
形式從該表中獲取所有數據,而不管從哪個表中獲取(它可以是來自table_1的1行,來自table_2的3行,然后又來自table_1的行)。 可能嗎? 怎么樣? 或喊我得到兩個查詢,然后用PHP按日期排序?
編輯:對不起,第一部分,我以為我可以從那里開始,但是好像我不能:/
我有這樣很大的查詢
SELECT
table_1.id,
table_1.created,
table_1.qty,
table_1.comments,
table_1.last_update,
table_7.firstname,
SUBSTRING(table_7.lastname, 1, 1) AS lastname,
table_8.title country,
table_3.value AS sim,
table_1.offer_request,
table_5.manufacturer AS manufacturer,
table_4.name AS model,
table_6.value AS specifications,
table_9.value as shipping,
table_1.model AS mid,
table_1.user_id,
table_1.callme,
table_1.phoneprice,
table_1.phoneprice_eur,
table_1.currency,
table_1.sel_buy_show_all,
table_1.seller_buyer
FROM (`table_1`)
LEFT JOIN `table_3` ON `table_3`.`id` = `table_1`.`sim`
LEFT JOIN `table_4` ON `table_4`.`id` = `table_1`.`model`
LEFT JOIN `table_5` ON `table_5`.`id` = `table_1`.`manufacturer`
LEFT JOIN `table_6` ON `table_6`.`id` = `table_1`.`specifications`
LEFT JOIN `table_7` ON `table_7`.`id` = `table_1`.`user_id`
LEFT JOIN `table_8` ON `table_7`.`country`=`table_8`.`id`
LEFT JOIN `table_9` ON `table_9`.`id` = `table_1`.`types`
WHERE `table_1`.`status` = '1'
AND `table_1`.`deleted` = '0'
ORDER BY `last_update` DESC
LIMIT 200
還有table_1的結構與table_2相同,並且我需要以某種方式將table_2插入到具有所有聯接的查詢中,例如table_1
如果我的問題正確,那么您可以使用工會-
select * from table_1 union select * from table_2 order by create_date desc
編輯
創建這樣的視圖-
create view table_1And2 as select * from table_1 union select * from table_2
table_1And2不是一個好名字,給一個有意義的名字。
然后像這樣修改您的長查詢-
SELECT
table_1And2.id,
table_1And2.created,
table_1And2.qty,
table_1And2.comments,
table_1And2.last_update,
table_7.firstname,
SUBSTRING(table_7.lastname, 1, 1) AS lastname,
table_8.title country,
table_3.value AS sim,
table_1And2.offer_request,
table_5.manufacturer AS manufacturer,
table_4.name AS model,
table_6.value AS specifications,
table_9.value as shipping,
table_1And2.model AS mid,
table_1And2.user_id,
table_1And2.callme,
table_1And2.phoneprice,
table_1And2.phoneprice_eur,
table_1And2.currency,
table_1And2.sel_buy_show_all,
table_1And2.seller_buyer
FROM (`table_1And2`)
LEFT JOIN `table_3` ON `table_3`.`id` = `table_1And2`.`sim`
LEFT JOIN `table_4` ON `table_4`.`id` = `table_1And2`.`model`
LEFT JOIN `table_5` ON `table_5`.`id` = `table_1And2`.`manufacturer`
LEFT JOIN `table_6` ON `table_6`.`id` = `table_1And2`.`specifications`
LEFT JOIN `table_7` ON `table_7`.`id` = `table_1And2`.`user_id`
LEFT JOIN `table_8` ON `table_7`.`country`=`table_8`.`id`
LEFT JOIN `table_9` ON `table_9`.`id` = `table_1And2`.`types`
WHERE `table_1And2`.`status` = '1'
AND `table_1And2`.`deleted` = '0'
ORDER BY `last_update` DESC
LIMIT 200
我也看到@Rehban的答案對您來說是一個好答案,如果您不需要view
,我將提供另一種解決方案:
SELECT
mainTable.id,
mainTable.created,
mainTable.qty,
mainTable.comments,
mainTable.last_update,
table_7.firstname,
SUBSTRING(table_7.lastname, 1, 1) AS lastname,
table_8.title country,
table_3.value AS sim,
mainTable.offer_request,
table_5.manufacturer AS manufacturer,
table_4.name AS model,
table_6.value AS specifications,
table_9.value as shipping,
mainTable.model AS mid,
mainTable.user_id,
mainTable.callme,
mainTable.phoneprice,
mainTable.phoneprice_eur,
mainTable.currency,
mainTable.sel_buy_show_all,
mainTable.seller_buyer
FROM (Select * From `table_1` union Select * From `table_2`) as mainTable
LEFT JOIN `table_3` ON `table_3`.`id` = `mainTable `.`sim`
LEFT JOIN `table_4` ON `table_4`.`id` = `mainTable `.`model`
LEFT JOIN `table_5` ON `table_5`.`id` = `mainTable `.`manufacturer`
LEFT JOIN `table_6` ON `table_6`.`id` = `mainTable `.`specifications`
LEFT JOIN `table_7` ON `table_7`.`id` = `mainTable `.`user_id`
LEFT JOIN `table_8` ON `table_7`.`country`=`table_8`.`id`
LEFT JOIN `table_9` ON `table_9`.`id` = `mainTable `.`types`
WHERE `mainTable `.`status` = '1'
AND `mainTable `.`deleted` = '0'
ORDER BY `last_update` DESC
LIMIT 200
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