[英]How to define route group name in laravel
有沒有辦法在 laravel 中定義路由組的名稱?
我試圖通過這個來完成的是知道當前請求屬於哪個組,這樣我就可以通過當前路由操作激活主菜單和子菜單:
代碼:
Route::group(['prefix'=>'accounts','as'=>'account.'], function(){
Route::get('/', 'AccountController@index')->name('index');
Route::get('connect', 'AccountController@connect')->name('connect');
});
Route::group(['prefix'=>'quotes','as'=>'quote.'], function(){
Route::get('/', 'QuoteController@index')->name('index');
Route::get('connect', 'QuoteController@create')->name('create');
});
導航 HTML 代碼
<ul>
<li> // Add class 'active' when any route is open from account route group
<a href="{{route('account.index')}}">Accounts</a>
<ul>
<li> // Add class 'active' when connect sub menu is clicked
<a href="{{route('account.connect')}}">Connect Account</a>
</li>
</ul>
</li>
<li> // Add class 'active' when any route is open from quote route group
<a href="{{route('quote.index')}}">Quotes</a>
<ul>
<li> // Add class 'active' when create sub menu is clicked
<a href="{{route('quote.create')}}">Create Quote</a>
</li>
</ul>
</li>
</ul>
現在我想要的是調用 function 或其他可以給我當前路線組名的東西。
例子:
getCurrentRouteGroup()
應該返回quote
getCurrentRouteGroup()
應該返回account
這應該工作:
Route::group(['prefix'=>'accounts','as'=>'account.'], function(){
Route::get('/', ['as' => 'index', 'uses' => 'AccountController@index']);
Route::get('connect', ['as' => 'connect', 'uses' = > 'AccountController@connect']);
});
更新
{{ $routeName = \Request::route()->getName() }}
@if(strpos($routeName, 'account.') === 0)
// do something
@endif
Rohit Khatri的替代方案
function getCurrentRouteGroup() {
$routeName = Illuminate\Support\Facades\Route::current()->getName();
return explode('.',$routeName)[0];
}
試試這個
Route::group(['prefix'=>'accounts','as'=>'account.'], function(){
Route::get('connect', [
'as' => 'connect', 'uses' => 'AccountController@connect'
]);
});
// both the format of defining the prefix are working,tested on laravel 5.6
Route::group(['prefix'=>'accounts','as'=>'account.'], function() {
Route::get('/', 'SomeController@index')->name('test');
Route::get('/new', function(){
return redirect()->route('account.test');
});
});
Route::group(['prefix' => 'admin', 'as' => 'admin.'], function () {
Route::get('/', [
'as' => 'custom',
'uses' => 'SomeController@index'
]);
Route::get('/custom', function(){
return route('admin.custom');
});
});
它應該工作 -
內刀片 -
{{ $yourRouteName = \Request::route()->getName() }}
// Find the first occurrence of account in URL-
@if(strpos($routeName, 'account.') === 0)
console the message or your code
@endif
您可以使用Route::name()->group(...)
為一組路由的所有名稱添加前綴
Route::name('foo.')->prefix('xyz')->group(function() {
Route::get('path', 'SomeController@method')->name('bar');
});
這里route('foo.bar')
解析為 url /xyz/path
查看相關的Laravel 文檔
不要忘記在前綴名稱中附加點:-)
在Laravel 9中,您現在可以執行以下操作:
Route::controller(AccountController::class)->group(function () {
Route::get('/', 'index')->name('index');
Route::get('/connect', 'connect')->name('connect');
});
laravel 9 文檔說: name 方法可用於為組中的每個路由名稱加上給定字符串的前綴。 例如,您可能希望在所有分組路由的名稱前加上 admin。 給定字符串的前綴與指定的路由名稱完全相同,因此我們將確保提供尾隨。 前綴中的字符:
Route::name('admin.')->group(function () {
Route::get('users', function () {
// Route assigned name "admin.users"...
})->name('users');
});
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