[英]How to check if a MySQL result is empty
// Populate headers
$fields = $result->fetch_fields();
foreach ($fields as $field)
printf("<th>%s</th>", $field->name);
printf("</tr>");
// Write to table
while ($myvar = $result->fetch_row()) {
$date = $myvar[0];
$room_ID = $myvar[1];
$description = $myvar[2];
$firstname = $myvar[3];
$lastname = $myvar[4];
$message = $myvar[5];
$period = $myvar[6];
printf("<tr>");
printf("<td>%s</td><td>%s</td>", $date, $room_ID);
printf("<td>%s</td><td>%s</td>", $description, $firstname);
printf("<td>%s</td><td>%s</td><td>%s</td>", $lastname, $message, $period);
printf("</tr>");
}
如果我的MySQLi結果返回空,我試圖回顯“無結果可顯示”。 問題是標題是作為數組的一部分返回的,我該如何實現呢?
您可以使用num_rows
來獲取從查詢中檢索到的記錄的總值。
$row_cnt = $result->num_rows;
if($row_cnt>0){ echo "Have data";}else{echo "No data";}
您需要檢查行數。 如果返回零,則表示表不包含任何行。 嘗試下面的代碼。
// Populate headers
$fields = $result->fetch_fields();
foreach ($fields as $field)
printf("<th>%s</th>", $field->name);
printf("</tr>");
// Write to table
if($result->num_rows== 0){
echo "No Result to display";
}else{
while ($myvar = $result->fetch_row()) {
$date = $myvar[0];
$room_ID = $myvar[1];
$description = $myvar[2];
$firstname = $myvar[3];
$lastname = $myvar[4];
$message = $myvar[5];
$period = $myvar[6];
printf("<tr>");
printf("<td>%s</td><td>%s</td>", $date, $room_ID);
printf("<td>%s</td><td>%s</td>", $description, $firstname);
printf("<td>%s</td><td>%s</td><td>%s</td>", $lastname, $message, $period);
printf("</tr>");
}
}
簡單使用num_rows
if($result->num_rows== 0){
echo "no results to display"
}
else{
while ($myvar = $result->fetch_row()) {
//Your Code here
}
您可以使用num_rows
來獲取記錄的總值。
$row_count = $result->num_rows;
if($row_count>0)
{
echo "Data Available";
}
else
{
echo "No Data Available";
}
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