[英]How to download a file in php
我在php中有這個函數用於下載文件,文件將用數據加密,然后下載
類:Connect只是與數據庫的連接
class License extends Connect {
function __construct() {
parent::__construct();
}
public function getLicense($vars){
// file_put_contents( "/var/log/datapost/clientinfo.log", date('r'). " ". var_export($vars,true) . PHP_EOL, FILE_APPEND );
$sql = "select * from License where license_id={$vars->data->license_id}";
$res = $vars->db->query( $sql );
if($obj=$res->fetch_object()){
$filename = "License".$vars->data->license_id.".json";
// get the private key
$pk = file_get_contents("/var/www/datapost/clientinfo/keys/key1.pem");
// // private key
$res = openssl_get_privatekey($pk,"passsword");
// // encrypt it
$x=openssl_private_encrypt( json_encode($obj),$crypttext,$res);
// save the encryption
//
file_put_contents("/var/www/datapost/clientinfo/license/license{$vars->data->license_id}}.json",$crypttext);
// header('Content-Description: File Transfer');
header('Content-Type: text/plain');
header('Content-Disposition: attachment; filename="' . $filename . '"');
// header('Expires: 0');
// header('Cache-Control: must-revalidate');
// header('Pragma: public');
// header('Content-Length: ' . strlen($crypttext));
echo $crypttext;
file_put_contents("/var/log/datapost/{$filename}", $crypttext, fopen("http://192.168.200.114/var/log/datapost/{$filename}", 'r' ));
flush();
file_put_contents( "/var/log/datapost/clientinfo.log", date('r'). " WOOHOO! $crypttext" . PHP_EOL, FILE_APPEND );
}
else {
file_put_contents( "/var/log/datapost/clientinfo.log", date('r'). " AAARG SHIT ".var_export($res,true) . PHP_EOL, FILE_APPEND );
}
}
}
但由於某種原因它沒有工作,數據是在http請求中發送但沒有文件正在下載數據,任何幫助表示贊賞
這是extjs應用程序中的ajax請求,(單擊按鈕時)
onButtonClick7: function(button, e, eOpts) {
Ext.Ajax.request({
url: 'system/index.php',
method: 'POST',
params: {
class: 'License',
method: 'getLicense',
data: Ext.encode({
license_id: Ext.getCmp('overviewGrid').selection.data.license_id
})
},
success: function( response ){
var object = Ext.decode( response.responseText, true );
//Ext.getStore('LicenseAllStore').reload();
// window.open('http://192.168.200.114/datapost/clientinfo/license/BLAH_BLAGH3.json');
},
failure: function( response ){
var object = Ext.decode( response.responseText, true );
Ext.MessageBox.alert( 'Status', object.message );
}
});
},
在這里它可以這樣做:
通過使用CURL:
$ch = curl_init();
$source = "http://someurl.com/afile.zip";
curl_setopt($ch, CURLOPT_URL, $source);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
$data = curl_exec ($ch);
curl_close ($ch);
$destination = "/asubfolder/afile.zip";
$file = fopen($destination, "w+");
fputs($file, $data);
fclose($file);
通過使用file_put_contents()
:
從PHP 5.1.0開始, file_put_contents()
支持通過將stream-handle作為$data
參數傳遞來逐個編寫:
file_put_contents("Tmpfile.zip", fopen("http://someurl/file.zip", 'r'));
從手冊:
如果數據 [即第二個參數]是流資源,則該流的剩余緩沖區將被復制到指定的文件。 這與使用
stream_copy_to_stream()
類似。
你問題的另一部分:
因為您正在嘗試將數組轉換為json,然后將該json代碼保存到文本文件中,所以,這是一種方法,您可以這樣做:
<?php
$data = array(
array('team_name' => "Team 1", 'wins' => "3", 'losses' => "0" ), //3
array('team_name' => "Team 2", 'wins' => "2", 'losses' => "1" ), //2
array('team_name' => "Team 3", 'wins' => "1", 'losses' => "2" ), //1
array('team_name' => "Team 4", 'wins' => "0", 'losses' => "3" ), //1
array('team_name' => "Team 5", 'wins' => "3", 'losses' => "0" ), //3
array('team_name' => "Team 6", 'wins' => "2", 'losses' => "1" ) ); //2
//if you want to just print the array here
echo json_encode($data);
// If you want to save the array into a text file
$json_file = fopen("array_into_json.txt" , "a") or die("Unable to open file!");
fwrite($json_file,json_encode($data). "\r\n");
fclose($json_file);
?>
注意:您可以對使用此代碼從數據庫中獲取的數組執行相同操作,只需將$data
數組替換為您的MySQLi數組。
實時代碼: https : //eval.in/562247
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