獲取 arangodb 中給定節點的連接節點列表

Question

我在 Arangodb 中構建了一個圖表。

我正在努力滿足以下要求。

給定一個節點，我需要一個連接到它的所有節點的列表以及它連接到的深度。

例子：

Customer2 -> 以 1 的深度連接到 Customer1，Customer3 -> 以 2 的深度連接到 Customer1，依此類推。

請幫助我實現這一目標。

Answer 1

假設您正在使用模式匹配遍歷，這很容易實現。

讓我們使用從Eve開始遍歷的Knows Graph示例進行嘗試：

db._query(`FOR v, e IN 1..3 OUTBOUND 'persons/eve' 
           GRAPH 'knows_graph' 
           RETURN {v: v, e: e}`)
[ 
  { 
    "e" : { 
      "_from" : "persons/eve", 
      "_id" : "knows/156", 
      "_key" : "156", 
      "_rev" : "156", 
      "_to" : "persons/alice" 
    }, 
    "v" : { 
      "_id" : "persons/alice", 
      "_key" : "alice", 
      "_rev" : "130", 
      "name" : "Alice" 
    } 
  }, 
  { 
    "e" : { 
      "_from" : "persons/alice", 
      "_id" : "knows/146", 
      "_key" : "146", 
      "_rev" : "146", 
      "_to" : "persons/bob" 
    }, 
    "v" : { 
      "_id" : "persons/bob", 
      "_key" : "bob", 
      "_rev" : "134", 
      "name" : "Bob" 
    } 
  }, 
  { 
    "e" : { 
      "_from" : "persons/bob", 
      "_id" : "knows/150", 
      "_key" : "150", 
      "_rev" : "150", 
      "_to" : "persons/charlie" 
    }, 
    "v" : { 
      "_id" : "persons/charlie", 
      "_key" : "charlie", 
      "_rev" : "137", 
      "name" : "Charlie" 
    } 
  }, 
  { 
    "e" : { 
      "_from" : "persons/bob", 
      "_id" : "knows/153", 
      "_key" : "153", 
      "_rev" : "153", 
      "_to" : "persons/dave" 
    }, 
    "v" : { 
      "_id" : "persons/dave", 
      "_key" : "dave", 
      "_rev" : "140", 
      "name" : "Dave" 
    } 
  }, 
  { 
    "e" : { 
      "_from" : "persons/eve", 
      "_id" : "knows/159", 
      "_key" : "159", 
      "_rev" : "159", 
      "_to" : "persons/bob" 
    }, 
    "v" : { 
      "_id" : "persons/bob", 
      "_key" : "bob", 
      "_rev" : "134", 
      "name" : "Bob" 
    } 
  }, 
  { 
    "e" : { 
      "_from" : "persons/bob", 
      "_id" : "knows/150", 
      "_key" : "150", 
      "_rev" : "150", 
      "_to" : "persons/charlie" 
    }, 
    "v" : { 
      "_id" : "persons/charlie", 
      "_key" : "charlie", 
      "_rev" : "137", 
      "name" : "Charlie" 
    } 
  }, 
  { 
    "e" : { 
      "_from" : "persons/bob", 
      "_id" : "knows/153", 
      "_key" : "153", 
      "_rev" : "153", 
      "_to" : "persons/dave" 
    }, 
    "v" : { 
      "_id" : "persons/dave", 
      "_key" : "dave", 
      "_rev" : "140", 
      "name" : "Dave" 
    } 
  } 
]

遍歷的每個步驟將映射到列表中的一個對象。 您還可以連接在V ertices（人）與_from和_to 電子當選總監的屬性（知道）

也只能看路徑。 您可以使用path屬性：

db._query(`FOR v, e, p IN 2..2 OUTBOUND 'persons/eve' 
           GRAPH 'knows_graph' 
           RETURN {p: p}`)

我們只返回迭代終點的路徑，將其限制為2，以便於更好地概述。 這是結果路徑之一：

[
  ...
  { 
    "p" : { 
      "edges" : [ 
        { 
          "_from" : "persons/eve", 
          "_id" : "knows/159", 
          "_key" : "159", 
          "_rev" : "159", 
          "_to" : "persons/bob" 
        }, 
        { 
          "_from" : "persons/bob", 
          "_id" : "knows/153", 
          "_key" : "153", 
          "_rev" : "153", 
          "_to" : "persons/dave" 
        } 
      ], 
      "vertices" : [ 
        { 
          "_id" : "persons/eve", 
          "_key" : "eve", 
          "_rev" : "143", 
          "name" : "Eve" 
        }, 
        { 
          "_id" : "persons/bob", 
          "_key" : "bob", 
          "_rev" : "134", 
          "name" : "Bob" 
        }, 
        { 
          "_id" : "persons/dave", 
          "_key" : "dave", 
          "_rev" : "140", 
          "name" : "Dave" 
        } 
      ] 
    } 
  } 
]

Answer 2

你需要這個

FOR col in collection
    FOR node,edge,path IN 1..50 OUTBOUND col GRAPH "graph_name"
        LET sub = (
            FOR vertices in path.vertices
                RETURN vertices._id
            )
        RETURN DISTINCT [node._id,LENGTH(sub)]