從各種活動中需要的資產加載多個位圖時，如何在android上節省資源

Question

很抱歉，長標題只想具體說明，所以我有一些活動，一旦開始，應該初始化資產中的所有位圖，下面的代碼可以工作，但是有更好的解決方案，請大家多多幫助。

初始化位圖的類：

public class Images {
private String[]eyes=new String[]{
        "images/character/face/eyes/blue.png"
};
public LinkedList<Bitmap> eyesBM=new LinkedList<Bitmap>();
private int eyesIndex = 0;

private String[]faceandhands=new String[]{
        "images/character/face/faceandhands/white.png",
        "images/character/face/faceandhands/black.png"
};
public LinkedList<Bitmap> faceandhandsBM=new LinkedList<Bitmap>();
private int faceandhandsIndex = 0;
private String[]facialhair=new String[]{
        "images/character/face/facialhair/black.png"
};

public LinkedList<Bitmap> facialhairBM=new LinkedList<Bitmap>();
private String[]hair=new String[]{
        "images/character/face/hair/grey.png"
};
public LinkedList<Bitmap> hairBM=new LinkedList<Bitmap>();
private String[]tattoes=new String[]{
        "images/character/face/tattoes/test.png"
};
public LinkedList<Bitmap> tattoesBM=new LinkedList<Bitmap>();
private String[]legs=new String[]{
        "images/character/legs/brown.png"
};
private LinkedList<Bitmap> legsBM=new LinkedList<Bitmap>();
private String[]shirt=new String[]{
        "images/character/shirt/purple.png"
};
public LinkedList<Bitmap> shirtBM=new LinkedList<Bitmap>();
private String[]shoes=new String[]{
        "images/character/shoes/red.png"
};
public LinkedList<Bitmap> shoesBM=new LinkedList<Bitmap>();
private String[]background=new String[]{
        "images/character/background/normal.png"
};
public LinkedList<Bitmap> backgroundBM=new LinkedList<Bitmap>();



public Images(Context c) {
    loadBitmaps(c,eyes,"eyes");
    loadBitmaps(c,faceandhands,"faceandhands");
    loadBitmaps(c,facialhair,"facialhair");
    loadBitmaps(c,hair,"hair");
    loadBitmaps(c,tattoes,"tattoes");
    loadBitmaps(c,legs,"legs");
    loadBitmaps(c,shirt,"shirt");
    loadBitmaps(c,shoes,"shoes");
    loadBitmaps(c,background,"background");
}

public Bitmap getBitmapFromAsset(Context context, String filePath) {
    AssetManager assetManager = context.getAssets();
    InputStream istr;
    Bitmap bitmap = null;
    try {
        istr = assetManager.open(filePath);
        bitmap = BitmapFactory.decodeStream(istr);
    } catch (IOException e) {
        System.out.println("Fudeu geral !");
    }

    return bitmap;
}
public void loadBitmaps(Context c,String[] src,String dest){
    Bitmap bit=null;
    for (int i = 0;i<src.length;i++){
        bit= getBitmapFromAsset(c,src[i]);
        switch (dest){
            case "eyes":
                eyesBM.add(bit);
                break;
            case "faceandhands":
                faceandhandsBM.add(bit);
                break;
            case "facialhair":
                facialhairBM.add(bit);
            break;
            case "hair":
                hairBM.add(bit);
            break;
            case "tattoes":
                tattoesBM.add(bit);
            break;
            case "legs":
                legsBM.add(bit);
            break;
            case "shirt":
                shirtBM.add(bit);
            break;
            case "shoes":
                shoesBM.add(bit);
            break;
            case "background":
                backgroundBM.add(bit);
            break;
        }
        //dest.add(bit);
        //dest.add(BitmapFactory.decodeResource(r, src[i]));
        }
}
public Bitmap getBitmap(String name){
    switch (name){
        case "eyes":
            eyesIndex=eyesIndex>=eyesBM.size()?0:eyesIndex;
            Bitmap aux =eyesBM.get(eyesIndex);
            eyesIndex++;
            return aux;
        case "faceandhands":
            faceandhandsIndex=faceandhandsIndex>=faceandhandsBM.size()?0:faceandhandsIndex;
            Bitmap aux1=faceandhandsBM.get(faceandhandsIndex);
            faceandhandsIndex++;
            return aux1;
            //return faceandhandsBM.get(0);
        case "facialhair":
            return facialhairBM.get(0);
        case "hair":
            return hairBM.get(0);
        case "tattoes":
            return tattoesBM.get(0);
        case "legs":
            return legsBM.get(0);
        case "shirt":
            return shirtBM.get(0);
        case "shoes":
            return shoesBM.get(0);
        case "background":
            return backgroundBM.get(0);
    }
    return null;
}}

´主要活動中的代碼：

setContentView(R.layout.activity_character);
    final EditText eT=(EditText)findViewById(R.id.characterName);
    v = (ImageView)findViewById(R.id.characterDisplay);
    img = new Images(this);
    LD=null;
    DD= new Drawable[]{
            new BitmapDrawable(img.getBitmap("legs")),
            new BitmapDrawable(img.getBitmap("faceandhands")),
            new BitmapDrawable(img.getBitmap("shirt")),
            new BitmapDrawable(img.getBitmap("eyes")),
            new BitmapDrawable(img.getBitmap("facialhair")),
            new BitmapDrawable(img.getBitmap("hair")),
            new BitmapDrawable(img.getBitmap("shoes")),
            new BitmapDrawable(img.getBitmap("tattoes"))
    };
    LD=new LayerDrawable(DD);
    v.setImageDrawable(LD);
    ((Button)findViewById(R.id.buttonSkin)).setOnClickListener(new View.OnClickListener() {
        public void onClick(View v) {
            DD[1]=new BitmapDrawable(img.getBitmap("faceandhands"));
            LD=new LayerDrawable(DD);
            update(LD);
            //saveCaracter(eT.getText().toString());
            //loadGame(eT.getText().toString());
        }
    });

更新方法：

private void update(LayerDrawable ld) {
    v.setImageDrawable(ld);
}

Answer 1

我知道的最簡單的方法是使用Picasso庫。 它減少了一噸的編碼。 http://square.github.io/picasso/