![](/img/trans.png)
[英]PHP SQL Server: Trying to find most recent entry into a database by the column Date and Time
[英]Find the column with the newest entry in sql using php
使用 php 代碼,如果我對 id 2 感興趣,我想知道最新條目位於哪一列。然后時間為“2016-03-01 10:01:01”的“time4”列是最新的入口。
id time1 time2 time3 time4
1 2016-01-01 09:27:24 2016-01-02 10:01:01 2016-01-02 17:05:07 2016-01-01 10:01:01
2 2016-01-02 09:27:24 2016-01-03 10:01:01 2016-02-02 17:05:07 2016-03-01 10:01:01
3 2016-01-02 10:27:24 2016-01-03 11:01:01 2016-02-02 18:05:07 2016-03-01 11:01:01
我試過這個
<?php
$User=1;
$result = $con->query("SELECT MAX(TimeToSelect) as Output
FROM (
SELECT time1 as TimeToSelect,id
FROM tableTime
union
SELECT time2,id
FROM tableTime
union
SELECT time3,id
FROM tableTime
union
SELECT time4,id
FROM tableTime
) as A
WHERE id = '$User'");
$row = $result->fetch_array(MYSQLI_BOTH);
echo $something=$row[0];
?>
但隨后它與日期“2016-03-01 10:01:01”相呼應,而不是列名“time4”。
如果你只包含 4 列進行比較,你可以使用下面的 SQL 來獲得你想要的。
您可以在 where 條件中更改 id 以獲取為特定“id”輸入的最新時間。 (每次每個id)
SELECT MAX(TimeToSelect) as Output
FROM (
SELECT time1 as TimeToSelect,id
FROM tableTime
union
SELECT time2,id
FROM tableTime
union
SELECT time3,id
FROM tableTime
union
SELECT time4,id
FROM tableTime
) as A
WHERE id = 1
如果要獲取列名,請嘗試以下 SQL:
SELECT ColumnName
FROM (
SELECT time1 AS TimeToSelect,id,'time1' AS ColumnName
FROM tableTime
UNION
SELECT time2,id,'time2'
FROM tableTime
UNION
SELECT time3,id,'time3'
FROM tableTime
UNION
SELECT time4,id,'time4'
FROM tableTime
) AS A
WHERE id = 1
AND TimeToSelect = (SELECT MAX(TimeToSelect)
FROM (
SELECT time1 AS TimeToSelect,id,'time1' AS ColumnName
FROM tableTime
UNION
SELECT time2,id,'time2'
FROM tableTime
UNION
SELECT time3,id,'time3'
FROM tableTime
UNION
SELECT time4,id,'time4'
FROM tableTime
) AS A
WHERE id = 1
)
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.