[英]Database error occurred in codeigniter
有人可以幫我查詢問題嗎? 當我執行它時,輸出顯示如下。
Error Number: 1064
你有一個錯誤
SQL語法; 檢查與您的MySQL服務器版本相對應的手冊,以在第1行的'?,?,?,?,?,?,?)'附近使用正確的語法
INSERT INTO touristspot(TouristspotID, AccountID, CategoryID, Name, Description, street, city_area, city) Values(0, 111, ?, ?, ?, ?, ?, ?)
我的控制器:
public function manager_spotdetails(){
$data = array(
'CategoryID' => $this->input->post('category'),
'Name' => $this->input->post('spotname'),
'Description' => $this->input->post('desc'),
'street' => $this->input->post('street'),
'city_area' => $this->input->post('city_area'),
'city' => $this->input->post('city')
);
$this->load->model('managerm');
$data['cat'] = $this->managerm->category();
$this->managerm->createspots($data);
$this->load->view('manager_spotdetails', $data);
}
public function createTouristspot(){
$this->load->model('managerm');
$data['cat'] = $this->managerm->category();
$this->load->view('manager_spotdetails');
}
我的模特:
public function createspots($data){
$b = $_SESSION['accountid'];
$this->db->trans_start();
$spot_id= $this->db->insert_id();
$sql3= "INSERT INTO touristspot(TouristspotID, AccountID, CategoryID, Name, Description, street, city_area, city) Values($spot_id, $b, ?, ?, ?, ?, ?, ?)";
$this->db->query($sql3, $data);
$this->db->trans_complete();
return $this->db->insert_id();
}
public function category(){
$this->db->select('CategoryID');
$this->db->select('CategoryType');
$this->db->from('category');
$query= $this->db->get();
return $query->result();
}
}
我的看法:
<div class="form-group">
<span class="input-group-addon" id="basic-addon1">Category Type</span>
<select class="form-control" name="category">
<?php foreach($cat as $row) {?>
<option value="<?php echo $row->CategoryID?>"><?php echo $row->CategoryType?></option>
<?php }?>
</select>
謝謝! :)
在添加引號后嘗試嘗試在SQL中將名稱列讀取為關鍵字
$sql3= "INSERT INTO touristspot(`TouristspotID`, `AccountID`, `CategoryID`, `Name`, `Description`, `street`, `city_area`, `city`) Values('$spot_id','$b', '', '', '','', '', '')";
更改$ sql3字符串,在VALUES中插入單引號('):
$sql3= "INSERT INTO touristspot(`TouristspotID`, `AccountID`, `CategoryID`, `Name`, `Description`, `street`, `city_area`, `city`) VALUES('$spot_id', '$b', ?, ?, ?, ?, ?, ?)";
使用此方法插入數據
控制者
$data = array(
"COLUMN_NAME"=>$this->input->post("account_fname"),
"COLUMN_NAME"=>$this->input->post("account_lname")
);
$insert = $this->Model_name->insert("table_name", $data);
模型
public function insert($table,$data){
$this->db->insert($table,$data);
$id = $this->db->insert_id();
return $id;
}
控制器中的方法manager_spotdetails應該是
public function manager_spotdetails(){
$data = array(
'AccountID'=>$_SESSION['accountid'],
'CategoryID' => $this->input->post('category'),
'Name' => $this->input->post('spotname'),
'Description' => $this->input->post('desc'),
'street' => $this->input->post('street'),
'city_area' => $this->input->post('city_area'),
'city' => $this->input->post('city')
);
$this->load->model('managerm');
$data['cat'] = $this->managerm->category();
$this->managerm->createspots($data);
$this->load->view('manager_spotdetails', $data);
}
模型中的方法createpots應為
public function createspots($data){
$this->db->trans_start();
$this->db->insert('touristspot', $data);
$this->db->trans_complete();
return $this->db->insert_id();
}
希望它能正常工作。 確保您的數組索引名稱與數據庫表列名稱相同。
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