[英]mysql left join and inner join 3 tables
我有 3 個表:oc_artists、oc_songs、oc_songs_tags
我可以使用此代碼選擇 2 個表:
SELECT * FROM `oc_songs` LEFT JOIN oc_songs_tags ON oc_songs.song_id=oc_songs_tags.song_id
WHERE oc_songs_tags.song_tag IS NULL
現在我需要從 oc_artists 中選擇數據...我試過這個問題的答案: MySQL LEFT JOIN 3 tables
這是我的代碼:
SELECT * FROM oc_songs
LEFT JOIN oc_artists
INNER JOIN oc_songs_tags
ON oc_songs.song_artist_id = oc_artists.artist_id
ON oc_songs_tags.song_id = oc_songs.song_id
但我收到此錯誤
8 errors were found during analysis.
Unrecognized keyword. (near "ON" at position 131)
Unexpected token. (near "oc_songs_tags" at position 134)
Unexpected token. (near "." at position 147)
Unexpected token. (near "song_id" at position 148)
Unexpected token. (near "=" at position 156)
Unexpected token. (near "oc_songs" at position 158)
Unexpected token. (near "." at position 166)
Unexpected token. (near "song_id" at position 167)
你的語法是錯誤的。 連接語法是:
[JOIN TYPE] JOIN [TABLE B] ON [TABLE A].[COLUMN] = [TABLE B].[COLUMN]
所以這意味着:
SELECT * FROM oc_songs
LEFT JOIN oc_artists ON oc_songs.song_artist_id = oc_artists.artist_id
INNER JOIN oc_songs_tags ON oc_songs.song_id = oc_songs_tags.song_id
理解 JOINS 的簡單方法是它們始終是 FROM 中列出的主表和您要 JOINING 的表之間的連接。 因此,將 JOIN 子句視為連詞列表。
因此,要將 TableA 與 TableB、TableC 和 TableD 連接起來,您可能有以下內容:
SELECT * FROM TableA
JOIN TableB on TableA.tableb_id = TableB.id -- this is first join
JOIN TableC on TableA.tablec_id = TableC.id -- this is second join
JOIN TableD on TableA.tabled_id = TableD.id -- this is third join
ON 子句的錯誤位置
SELECT * FROM oc_songs
LEFT JOIN oc_artists ON oc_songs.song_artist_id = oc_artists.artist_id
INNER JOIN oc_songs_tags ON oc_songs_tags.song_id = oc_songs.song_id
示例表:
DROP TABLE IF EXISTS `oc_songs` ;
DROP TABLE IF EXISTS `oc_songs_tags` ;
DROP TABLE IF EXISTS `oc_artists` ;
CREATE TABLE `oc_songs` (
`song_id` int(10) unsigned NOT NULL auto_increment,
`song_name` varchar(255) NOT NULL,
`song_artist_id` int(10),
PRIMARY KEY (`song_id`),
foreign key (`song_artist_id`) references oc_artists(`artist_id`)
) ENGINE=MyISAM AUTO_INCREMENT=1 DEFAULT CHARSET=latin1;
CREATE TABLE `oc_songs_tags` (
`song_tag_id` int(10) unsigned NOT NULL auto_increment,
`song_tag` varchar(255) NOT NULL,
`song_id` int(10),
PRIMARY KEY (`song_tag_id`),
foreign key (`song_id`) references oc_songs(`song_id`)
) ENGINE=MyISAM AUTO_INCREMENT=1 DEFAULT CHARSET=latin1;
CREATE TABLE `oc_artists` (
`artist_id` int(10) unsigned NOT NULL auto_increment,
`artist_age` int(4),
PRIMARY KEY (`artist_id`)
) ENGINE=MyISAM AUTO_INCREMENT=1 DEFAULT CHARSET=latin1;
右鍵選擇:
SELECT * FROM oc_songs
LEFT JOIN oc_artists ON
oc_songs.song_artist_id = oc_artists.artist_id
INNER JOIN oc_songs_tags ON
oc_songs.song_id = oc_songs_tags.song_id;
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.