SQL，Case with Like里面的地方

Question

有人可以幫我嗎？ 我有一個具有這種結構的字段：2,3,4,5,6,0,1它們是星期幾，我必須找到當今天是本周的最后一個交付日時，問題是：

例如，今天是第3天，通過以下查詢，我可以選擇所有以3號結尾的人，但如果我有一個具有這種結構的人：3,0,1，或3,1或3,0我不知道得到他們。

declare @today int
set @today=DATEPART(dw,GETDATE())-2
print @today
select cast (cfv.value as VARCHAR)
from CompanyFieldvalues cfv
join CompanyFields cf on cf.companyFieldId=cfv.companyFieldId
where cf.name='NextDeliveryDates' and cfv.companyId in(
select cfv.companyId
from CompanyFieldvalues cfv
join Companies c on c.companyId=cfv.companyId
where cfv.value='Retailer' and c.status=1)
and (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' + cast (@today as VARCHAR))

要修復它我很難介紹一個案例，所以我的查詢將是這一個：

declare @today int
set @today=DATEPART(dw,GETDATE())-2
print @today
select cast (cfv.value as VARCHAR)
from CompanyFieldvalues cfv
join CompanyFields cf on cf.companyFieldId=cfv.companyFieldId
where cf.name='NextDeliveryDates' and cfv.companyId in(
select cfv.companyId
from CompanyFieldvalues cfv
join Companies c on c.companyId=cfv.companyId
where cfv.value='Retailer' and c.status=1)
and (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' + cast (@today as VARCHAR))  and  case
        when (@today != 0 or @today!=1) 
        then (cfv.value not like '%,0' or cfv.value not like '%,1')

但在這種情況下，我收到此錯誤消息：

消息156，級別15，狀態1，行14關鍵字'not'附近的語法不正確。

我確定我犯了一些愚蠢的錯誤，但我不明白：S

一些幫助請！ 非常感謝

Answer 1

您可以使用邏輯表達式替換CASE語句：

(((@today != 0 or @today!=1) AND (cfv.value not like '%,0' or cfv.value not like '%,1')) OR NOT (@today != 0 or @today!=1))

所以你的查詢將成為：

declare @today int
set @today=DATEPART(dw,GETDATE())-2
print @today
select cast (cfv.value as VARCHAR) from CompanyFieldvalues cfv
    join CompanyFields cf on cf.companyFieldId=cfv.companyFieldId
    where cf.name='NextDeliveryDates' and cfv.companyId in(
        select cfv.companyId
            from CompanyFieldvalues cfv
            join Companies c on c.companyId=cfv.companyId
            where cfv.value='Retailer' and c.status=1) 
            and (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value     like '%' + cast (@today as VARCHAR)) 
            and  (((@today != 0 or @today!=1) AND (cfv.value not like '%,0' or cfv.value not like '%,1')) OR NOT (@today != 0 or @today!=1))

Answer 2

使用CASE語句應該看起來像這樣：

declare @today int
set @today=DATEPART(dw,GETDATE())-2
print @today

select cfv.value
from CompanyFieldvalues cfv
join CompanyFields cf on cf.companyFieldId=cfv.companyFieldId
where cf.name='NextDeliveryDates' and cfv.companyId in(
select cfv.companyId
from CompanyFieldvalues cfv
join Companies c on c.companyId=cfv.companyId
where cfv.value='Retailer' and c.status=1)

and

CASE
    WHEN (@today !=0 or @today!=1) THEN
        (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' + cast    (@today as VARCHAR) 
        or cfv.value like '%' + cast (@today as VARCHAR)+',0'
        or cfv.value like '%' + cast (@today as VARCHAR)+',0,1'
        or cfv.value like '%' + cast (@today as VARCHAR)+',1')
    ELSE
        (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' +  cast  (@today as VARCHAR))
END = 1

要么 *************************************

 CASE
    WHEN ((@today !=0 or @today!=1) AND (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' + cast    (@today as VARCHAR) 
        or cfv.value like '%' + cast (@today as VARCHAR)+',0'
        or cfv.value like '%' + cast (@today as VARCHAR)+',0,1'
        or cfv.value like '%' + cast (@today as VARCHAR)+',1'))
    THEN 1
    WHEN (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' +  cast  (@today as VARCHAR)) THEN 1
    ELSE 0
END = 1

但確實表達式（@today！= 0或@today！= 1）始終為真。 也許你應該找到另一個有意義的條件

Answer 3

帕特里夏的最新消息：

這是我的表，它只有一行，這個值代表一個人的最后一個交付日，問題是他們有這個結構：2,3,4,5,6,0,1

3,0,1
0,1
3,0
5,6
5,5
5
3

我需要知道這個人中的一個是否像今天一樣有最后一個交貨日（0和1每次都在最后但實際上它們不是最后一個交貨日，而是第一個和第二個交貨日）。

我想我必須為0和1創建2個獨立的案例，但是我沒有得到它們：S這就是我實際擁有的：

declare @today int
set @today=DATEPART(dw,GETDATE())-2 /*-2 because the date are managed from a c# code so I need in this way to have the day in the format Monday=0, etc*/
print @today
select cfv.value
from CompanyFieldvalues cfv
join CompanyFields cf on cf.companyFieldId=cfv.companyFieldId
where cf.name='NextDeliveryDates' and cfv.companyId in(
select cfv.companyId
from CompanyFieldvalues cfv
join Companies c on c.companyId=cfv.companyId
where cfv.value='Retailer' and c.status=1)
and
 CASE
    WHEN ((@today !=0 or @today!=1) AND (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' + cast    (@today as VARCHAR) 
    or cfv.value like '%' + cast (@today as VARCHAR)+',0'
    or cfv.value like '%' + cast (@today as VARCHAR)+',0,1'
    or cfv.value like '%' + cast (@today as VARCHAR)+',1'))
    then 1
    WHEN (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' +  cast  (@today as VARCHAR)) THEN 1
    ELSE 0
END = 1

在這一刻，正如你所說，我每次都有問題，當它是第0天或第1天。如果是第0天我必須只選擇值= 0，何時是第1天我必須選擇何時值= 1或值= 0 ，1所以我認為我需要修改第二個條件：

WHEN (cfv.value like '%,' + cast (@today as VARCHAR) or cfv.value like '%' +  cast  (@today as VARCHAR)) THEN 1

並創造2個不同的不是嗎？

Answer 4

如果我是你，我理解你打算做什么，我會按照以下方式實現。 我會定義一個分割你的字符串的函數：

create function dbo.SplitString 
(
    @str nvarchar(max), 
    @separator char(1)
)
returns table
AS
return (
with tokens(p, a, b) AS (
    select 
        cast(1 as bigint), 
        cast(1 as bigint), 
        charindex(@separator, @str)
    union all
    select
        p + 1, 
        b + 1, 
        charindex(@separator, @str, b + 1)
    from tokens
    where b > 0
)
select
    p-1 ItemIndex,
    substring(
        @str, 
        a, 
        case 
        when b > 0 then b-a 
        ELSE LEN(@str) end) 
    AS Item
from tokens
);

GO

然后我會使用以下條件：

AND where not exists(select * from dbo.SplitString(cfv.value, ',') where    CAST(Item AS INT) > @today )   

我測試了你給我的樣品並且它有效。 所以對於以下輸入：

5 
5 
3,4
5 
5 
5 
3,0,1 
3,0 
5 
3

它返回：

3
3,0,1
3,0