通過比較mysql中的兩個日期獲取數據

Question

我每周獲取一次旅行詳細信息，並計算出他在客戶所在地所花費的工作時間。下面有一位員工從2016年4月3日到2016年4月30日外出旅行，該月該員工的可用記錄僅為一個。

43  3   International   Moho    Nether  2016-04-03 14:29:12 2016-04-30 14:29:12 Demo

我只是想按周檢索記錄。 所以我嘗試了一個查詢，它返回某些日期的行，有時卻沒有。 我只是用星期幾嘗試了這三個查詢。

//Last week of april (25th Apr to 1st May)
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) >= '2016-04-25' and date(return_date) <= '2016-05-01');    //0 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) <= '2016-04-25' or '2016-05-01' <=  date(return_date));   //1 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and ((date(travel_date) >= '2016-04-25' and date(travel_date) <= '2016-05-01' ) or (date(return_date) >= '2016-04-25' and date(return_date) <= '2016-05-01'));  //1 row(s) returned

//Fourth week  (18th Apr to 24th Apr)
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) >= '2016-04-18' and date(return_date) <= '2016-04-24');  //0 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) <= '2016-04-18' or '2016-04-24' <=  date(return_date));  //1 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and ((date(travel_date) >= '2016-04-18' and date(travel_date) <= '2016-04-24' ) or (date(return_date) >= '2016-04-18' and date(return_date) <= '2016-04-24'));   //0 row(s) returned

//Third week  (11th Apr to 17th Apr)
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) >= '2016-04-11' and date(return_date) <= '2016-04-17');  //0 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) <= '2016-04-11' or '2016-04-17' <=  date(return_date));  //1 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and ((date(travel_date) >= '2016-04-11' and date(travel_date) <= '2016-04-17' ) or (date(return_date) >= '2016-04-11' and date(return_date) <= '2016-04-17'));  //0 row(s) returned

//Sec week  (4th Apr to 10th Apr)
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) >= '2016-04-04' and date(return_date) <= '2016-04-10'); //0 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) <= '2016-04-04' or '2016-04-10' <=  date(return_date)); //1 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and ((date(travel_date) >= '2016-04-04' and date(travel_date) <= '2016-04-10' ) or (date(return_date) >= '2016-04-04' and date(return_date) <= '2016-04-10')); //0 row(s) returned

//Firs week  (28th Mar to 3rd   Apr)
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) >= '2016-03-28' and date(return_date) <= '2016-04-03'); //1 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) <= '2016-03-28' or '2016-04-03' <=  date(return_date)); //1 row(s) returned
SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and ((date(travel_date) >= '2016-03-28' and date(travel_date) <= '2016-04-03' ) or (date(return_date) >= '2016-03-28' and date(return_date) <= '2016-04-03')); //1 row(s) returned

通過以上測試，第二個查詢在所有條件下均有效。 但是，當我在PHP文件中使用它時，第二次查詢在該日期（4月25日至5月1日）仍然無效。

PHP coding:
///////////Employee Outstation(Travel) details/////////////
        $employeeTravel = new EmployeeTravelRecord();   
        $TravelEntryList = $employeeTravel->Find("employee = ? and (date(travel_date) <= ? and ? <=  date(return_date))",array($employeeId,$start,$end));
    //  $TravelEntryList = $employeeTravel->Find("employee = ? and ((travel_date >= ? and travel_date <= ? ) or (return_date >= ? and return_date <= ?))",array($employeeId,$start,$end,$start,$end));      
        $startdate = $start;
        $enddate = $end;
        $TravelTime = 0;
        foreach($TravelEntryList as $Travelentry){          
                $TraveldateArr = explode(" ",$Travelentry->travel_date);
                $Traveldate = $TraveldateArr[0];                
                $ReturndateArr = explode(" ",$Travelentry->return_date);
                $Returndate = $ReturndateArr[0];                
                if($startdate >= $Traveldate)
                {$firstdate = $startdate;
                }
                else
                    $firstdate = $Traveldate;

                if($enddate <= $Returndate )
                {
                    $lastdate = $enddate;
                }
                else
                    $lastdate = $Returndate;

                $holidays = $this->getholidays($firstdate,$lastdate);

                $totalhours = $this->getWorkingDays($firstdate,$lastdate,$holidays);                    
                $amount = $totalhours;
                error_log("totalhours" . $totalhours);
                $TravelTime += $amount;     
        }

我不知道錯誤在哪里，為了僅通過兩個日期（旅行日期和返回日期）來獲得每周記錄，哪一個最好？

我跟蹤了第三個查詢，以獲取雇員離職日期和離職日期來逐周獲取雇員離職。 但這在那很好。 這就是為什么我選擇它作為旅行記錄的原因。 但是，這里第3條查詢不適用於所有情況。

同一第二查詢在一周中返回1行（5月9日-5月15日）

SELECT * FROM simhrmdb.employeetravelrecords where employee = 3 and (date(travel_date) <= '2016-05-09' and '2016-05-15' <=  date(return_date));

我如何避免這種情況？

Answer 1

您正在使用or條件來驗證SQL查詢中的日期列（ ... <= '2016-04-25' or '2016-05-01' <= ... ），但是在PHP腳本中，您正在使用AND而不是or子句（ ... <= ? and ? <= ... ）。 嘗試更改條件<= ? **or** ? <= <= ? **or** ? <= <= ? **or** ? <=取代and用or ），並檢查是相同的。

TravelEntryList = $employeeTravel->Find("employee = ? 
and (date(travel_date) <= ? or ? <=  date(return_date))",array($employeeId,$start,$end));