如何獲取SQL查詢HAVING count顯示具有INNER JOIN存在的相同值的BOTH記錄

Question

這是當前的查詢：

SELECT schedule.routenr, stops.stopname, schedule.scheduletime FROM schedule 
INNER JOIN stops ON
schedule.id_stop=stops.id_stop
INNER JOIN tram ON
schedule.id_tram=tram.id_tram
WHERE tram.id_direction = '5' AND  stops.stopname = 'Stourton' AND 
schedule.scheduletime >= ('10:50:00') 
OR tram.id_direction = '5' AND stops.stopname = 'CitySquare'

ORDER BY schedule.routenr ASC, schedule.scheduletime ASC;

這些是顯示的結果：

route_nr    stopname      scheduletime

1           CitySquare    09:57:00
2           Stourton      11:50:00
2           CitySquare    11:57:00  
3           Stourton      12:50:00 
3           CitySquare    12:57:00

查詢結果添加了HAVING COUNT（schedule.routenr）> 1

route_nr    stopname      scheduletime
2           Stourton      11:50:00

我希望能夠在route_nr中顯示具有重復計數的兩個記錄，以便顯示stopname = Stourton和stopname = CitySquare。 這是它應該顯示的內容。

route_nr    stopname      scheduletime

2           Stourton      11:50:00
2           CitySquare    11:57:00  
3           Stourton      12:50:00 
3           CitySquare    12:57:00

這是包含數據的表列表：

tram                                   stops
id_tram  id_direction                  id_stop  stopname
1        1                             1        GrimesDyke
2        1                             2        SeacroftRingRoad 
3        1                             3        WykeBeck
4        1                             4        FfordeGrene
5        2                             5        St.James'sHospital
6        2                             6        QuarryHill
7        2                             7        Eastgate
8        2                             8        CitySquare
9        2                             9        Bodington
10       2                             10       HeadingleyCentre
11       3                             11       HydeParkCorner
12       3                             12       UniversityofLeeds
13       3                             13       Civic
14       4                             14       Riverside
15       5                             15       ClarenceDock
                                       16       StJoseph's
                                       17       ChurchStreet
                                       18       Stourton
                                       19       BalmRoad
                                       20       BelleIsleNorth
                                       21       BelleIsleCentral
                                       22       BelleIsleSouth
                                       23       MiddletonDistrictCentre
                                       24       MiddletonCircus
                                       25       Tingley

schedule
id_schedule   id_tram   id_stop  routenr  scheduletime
1             15        18       1        09:50:00
2             15        18       2        11:50:00
3             15        18       3        12:50:00
4             15        8        1        09:57:00
5             15        8        2        11:57:00
6             15        8        3        12:57:00
7             15        8        1        09:42:00
8             14        18       1        09:49:00
9             14        8        2        11:42:00
10            14        18       2        11:49:00

Answer 1

也許將每個route_nr的記錄放在route_nr上就足夠了。 如果是這樣的話：

SELECT s.routenr, GROUP_CONCAT(st.stopname ORDER BY s.scheduletime) as stopnames,
       GROUP_CONCAT(s.scheduletime ORDER BY s.scheduletime) as schedules
FROM schedule s INNER JOIN
     stops st
     ON s.id_stop = st.id_stop INNER JOIN
     tram t
     ON s.id_tram = t.id_tram
WHERE (t.id_direction = '5' AND  st.stopname = 'Stourton' AND 
s.scheduletime >= '10:50:00') OR
      (t.id_direction = '5' AND st.stopname = 'CitySquare')
GROUP BY s.routenr
HAVING COUNT(*) > 1;

如果你真的想要原始的行，那么你需要一個更復雜的查詢，這在MySQL中很麻煩（但在其他數據庫中卻沒有）。 一種方法是重復外部查詢的邏輯：

SELECT s.routenr, st.stopname, s.scheduletime
FROM schedule s INNER JOIN
     stops st
     ON s.id_stop = st.id_stop INNER JOIN
     tram t
     ON s.id_tram = t.id_tram
WHERE ((t.id_direction = '5' AND  st.stopname = 'Stourton' AND 
s.scheduletime >= '10:50:00') OR
       (t.id_direction = '5' AND st.stopname = 'CitySquare')
      ) AND
      s.routenr IN (SELECT s.routenr
                    FROM schedule s INNER JOIN
                         stops st
                         ON s.id_stop = st.id_stop INNER JOIN
                         tram t
                         ON s.id_tram = t.id_tram
                    WHERE (t.id_direction = '5' AND  st.stopname = 'Stourton' AND s.scheduletime >= '10:50:00') OR
                          (t.id_direction = '5' AND st.stopname = 'CitySquare')
                    GROUP BY s.routenr
                    HAVING COUNT(*) > 1
                  );

Answer 2

SELECT schedule.routenr, stops.stopname, schedule.scheduletime FROM schedule 
INNER JOIN stops ON
schedule.id_stop=stops.id_stop
INNER JOIN tram ON
schedule.id_tram=tram.id_tram
WHERE tram.id_direction = '5' AND  stops.stopname = 'Stourton' AND 
schedule.scheduletime >= ('10:50:00') OR tram.id_direction = '5' AND 
stops.stopname = 'CitySquare' AND schedule.routenr 
in (SELECT s.routenr FROM schedule s
INNER JOIN stops ON
schedule.id_stop=stops.id_stop
INNER JOIN tram ON
schedule.id_tram=tram.id_tram
WHERE tram.id_direction = '5' AND  stops.stopname = 'Stourton' AND 
schedule.scheduletime >= ('10:50:00') 
OR tram.id_direction = '5' AND stops.stopname = 'CitySquare'
GROUP BY s.routenr
HAVING COUNT(*) > 1);

Answer 3

你可以用這個：

select tmp.routenr, maintable.stopname, maintable.scheduletime 
from(
    SELECT sc.routenr, st.stopname, sc.scheduletime 
    FROM schedule sc
    INNER JOIN stops st
        ON sc.id_stop = st.id_stop
    INNER JOIN tram tr
        ON sc.id_tram = tr.id_tram
    WHERE tr.id_direction = '5' AND  st.stopname = 'Stourton' AND 
        sc.scheduletime >= ('10:50:00') 
        OR tr.id_direction = '5' AND st.stopname = 'CitySquare'
     ) maintable
inner join ( 
    SELECT sc1.routenr, count(*) as routenr_count
    FROM schedule sc1
    INNER JOIN stops st1
        ON sc1.id_stop = st1.id_stop
    INNER JOIN tram 
        ON sc1.id_tram = tr1.id_tram
    WHERE tr1.id_direction = '5' AND  st1.stopname = 'Stourton' AND 
        sc1.scheduletime >= ('10:50:00') 
        OR tr1.id_direction = '5' AND st1.stopname = 'CitySquare'
    group by sc1.routenr
    ) tmp
on tmp.routenr = maintable.routenr
where tmp.routenr_count > 1
ORDER BY maintable.routenr ASC, maintable.scheduletime ASC;

我想知道or條款，你能證實它是對的嗎？ 因為我覺得應該是這樣的

where (tram.id_direction = '5' AND  stops.stopname = 'Stourton' AND 
        schedule.scheduletime >= ('10:50:00') 
      )
      OR 
      (tram.id_direction = '5' AND stops.stopname = 'CitySquare'
      )

編輯：已更改，因此它可用作示例數據。 另一個解決方案應該是來自Gordon Linoff （ route_nr in (...)第二個解決方案route_nr in (...)在他的查詢中首先糾正你的OR意圖）

Answer 4

解決此問題的另一種方法是使用變量模擬row_number ，以按升序和降序按schedule_time枚舉每個route_nr組中的行。 其中一個行號大於1的所有行都是具有多於1行的route_nr組的一部分：

SELECT * FROM (
    SELECT * ,
        @prevc2 := IF(@prev2 = routenr, @prevc2+1, 1) rn2,
        @prev2 := routenr
    FROM (
        SELECT schedule.routenr, stops.stopname, schedule.scheduletime,
            @prevc1 := IF(@prev1 = schedule.routenr, @prevc1+1, 1) rn1,
            @prev1 := schedule.routenr
        FROM schedule 
        INNER JOIN stops ON
        schedule.id_stop=stops.id_stop
        INNER JOIN tram ON
        schedule.id_tram=tram.id_tram
        WHERE tram.id_direction = '5' AND  stops.stopname = 'Stourton' AND 
        schedule.scheduletime >= ('10:50:00') 
        OR tram.id_direction = '5' AND stops.stopname = 'CitySquare'
        ORDER BY schedule.routenr ASC, schedule.scheduletime ASC
    ) t 
    ORDER BY routenr ASC, scheduletime DESC
) t WHERE rn1 > 1 OR rn2 > 1