如何使用GROUP BY連接SQL Server中的不同列？

Question

如何得到：

ID  Description     Details
1   A               Details 1
1   B               Details 2
2   A               Details 3
2   A               Details 4
2   B               Details 5
3   B               Details 6
3   B               Details 7
3   B               Details 8

至：

ID  Values
1   A: Details 1 - B: Details 2
2   A: Details 3, Details 4 - B:Details 5
3   B: Details 6, Details 7, Details 8

我嘗試遵循此線程中的解決方案： 如何使用GROUP BY在SQL Server中連接字符串？

但這給出了：

ID  Values
1   A: Details 1 - B: Details 2
2   A: Details 3, A: Details 4 - B:Details 5
3   B: Details 6, B:Details 7, B:Details 8

有沒有一種方法可以不重復結果集中的描述列？

謝謝！

Answer 1

使用ROW_NUMBER僅在第一項上添加Description ：

WITH Cte AS(
    SELECT *,
        rn = ROW_NUMBER() OVER(PARTITION BY Id, Description ORDER BY Details)
    FROM #tbl
)
SELECT
    ID,
    [Values] =
        STUFF((
            SELECT 
                CASE WHEN rn = 1 THEN ' - ' + Description + ': ' ELSE ', ' END  + Details
            FROM Cte
            WHERE Id = t.Id
            ORDER BY Description, Details
            FOR XML PATH(''),TYPE).value('(./text())[1]','VARCHAR(MAX)')
        , 1, 2, '') 
FROM #tbl t
GROUP BY Id

在線演示

Answer 2

我已經修改了查詢以獲取所需的輸出。請將#tew替換為您的表名。 希望對您有幫助。

;with cte as 
(SELECT distinct ID,Description + ':' +
         STUFF(
               (SELECT      ',' + SubTableUser.Details
               FROM      #tew AS SubTableUser
               WHERE      SubTableUser.ID = outerTable.ID and SubTableUser.Description = outerTable.Description
               FOR XML PATH('')), 1, 1, '') AS Details

FROM   #tew as outerTable
 )
select distinct ID,
         STUFF(
               (SELECT      ',' + SubTableUser.Details
               FROM      cte AS SubTableUser
               WHERE      SubTableUser.ID = outerTable.ID 
               FOR XML PATH('')), 1, 1, '') AS Details

FROM  cte as outerTable
order by ID