Mysql計算上次結束時間和當前開始之間的分鍾，以記錄系統停機時間

Question

根據系統行，我需要幫助，我需要計算上次結束日期和當前事件的開始日期之間的分鍾差。

這是表格：

id |system |start |end | ------------------------------------------------------------ 2 | system 1 | 2016-01-01 12:00:00 | 2016-01-01 13:00:00 | ------------------------------------------------------------ 3 | system 1 | 2016-01-02 11:00:00 | 2016-01-02 12:00:00 | ------------------------------------------------------------ 5 | system 1 | 2016-01-03 15:00:00 | 2016-01-03 16:00:00 | ------------------------------------------------------------ 6 | system 2 | 2016-01-01 10:00:00 | 2016-01-01 11:00:00 | ------------------------------------------------------------ 7 | system 2 | 2016-01-02 17:00:00 | 2016-01-02 18:00:00 |

結果是：

標識為2和6的兩個系統記錄沒有“結束日期”的先前記錄以進行減法：

id | system | diff_min | --------------------------------- 2 | system 1 | 0 | --------------------------------- 3 | system 1 | 1380 | --------------------------------- 5 | system 1 | 1620 | --------------------------------- 6 | system 2 | 0 | --------------------------------- 7 | system 2 | 1800 | ---------------------------------

Answer 1

您可以使用兩個內置函數來實現

 select id, system, TIMESTAMPDIFF(MINUTE, endDate, startDate)  diff_min

要么

 select id, system, TIMEDIFF(endDate, startDate)/60 as  diff_min

Answer 2

 select  id,system,TIMESTAMPDIFF(MINUTE,end,start) as diff_min from table_name;

Answer 3

下面的查詢執行此操作：

SELECT
    id,
    system,
    IF (@previousSystem = system, TIMESTAMPDIFF(MINUTE ,@previousEndTime,start), 
        @previousEndTime := 0) diff_min,
    @previousSystem := system,
    @previousEndTime := end
FROM
    system_table,
    (
        SELECT
            @previousSystem := NULL,
            @previousEndTime := '0000-00-00 00:00:00'
    ) var
ORDER BY system, id;

輸出：

對您的給定數據運行以上查詢，您將獲得如下輸出：

id  system      diff_min
2   system 1    0
3   system 1    1320
5   system 1    1620
6   system 2    0
7   system 2    1800

SQL字段

請忽略查詢結果集中的最后兩列