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[英]Iterating through json array with appended json string in android after json as response from url using volley
[英]Iterating through JSonArray response from url using android volley
這是我的JSonArray
{
"vendor":[
{
"vendor_name":"Tapan Moharana",
"vendor_description":"",
"vendor_slug":"tapan",
"vendor_logo":null,
"contact_number":null
}
],
"products":[
{
"name":"Massage",
"price":"5000.0000",
"image":"http:\/\/carrottech.com\/lcart\/media\/catalog\/product\/cache\/1\/image\/150x\/9df78eab33525d08d6e5fb8d27136e95\/2\/9\/29660571-beauty-spa-woman-portrait-beautiful-girl-touching-her-face.jpg"
},
{
"name":"Chicken Chilly",
"price":"234.0000",
"image":"http:\/\/carrottech.com\/lcart\/media\/catalog\/product\/cache\/1\/image\/150x\/9df78eab33525d08d6e5fb8d27136e95\/c\/h\/cheicken.jpg"
},
{
"name":"Chicken Biryani",
"price":"500.0000",
"image":"http:\/\/carrottech.com\/lcart\/media\/catalog\/product\/cache\/1\/image\/150x\/9df78eab33525d08d6e5fb8d27136e95\/placeholder\/default\/image_1.jpg"
}
]
}
這是我的Java代碼:
JSONObject jsono = new JSONObject(response);
JSONArray children = jsono.getJSONArray("vendor");
JSONArray childrenProducts = jsono.getJSONArray("products");
for (int i = 0; i <children.length(); i++) {
JSONObject jsonData = children.getJSONObject(i);
System.out.print(jsonData.getString("vendor_name") + "<----");
// String vendorThumbNailURL=jsonData.getString("")
//jvendorImageURL.setImageUrl(local, mImageLoader);
vendorLogo=vendorLogo+jsonData.getString("vendor_logo").trim();
jvendorImageURL.setImageUrl(vendorLogo, mImageLoader);
jvendorName.setText(jsonData.getString("vendor_name"));
jvendorAbout.setText(jsonData.getString("vendor_description"));
jvendorContact.setText(jsonData.getString("contact_number"));
System.out.print(jsonData.getString("products") + "<----");
}
for(int i=0;i<childrenProducts.length();i++){
JSONObject jsonData = childrenProducts.getJSONObject(i);
System.out.println("inside products");
System.out.print(jsonData.getString("name") + "<----dd");
}
第一個for循環工作正常,但第二個forloop則工作不正常。如果我嘗試在第二個for循環內執行這些打印語句,我什么也沒得到。
為什么不使用Gson來簡單地解析JSON字符串?
您需要先聲明類,以匹配JSON響應,如下所示。
public class Vendor {
private String vendor_name;
private String vendor_description;
private String vendor_slug;
private String vendor_logo;
private String contact_number;
public Vendor() {
}
public String getVendor_name() {
return vendor_name;
}
public String getVendor_description() {
return vendor_description;
}
public String getVendor_slug() {
return vendor_slug;
}
public String getVendor_logo() {
return vendor_logo;
}
public String getContact_number() {
return contact_number;
}
}
...
public class Product {
private String name;
private String price;
private String image;
public Product() {
}
public String getName() {
return name;
}
public String getPrice() {
return price;
}
public String getImage() {
return image;
}
}
現在像這樣聲明Response
類
public class Response {
private List<Vendor> vendor;
private List<Product> products;
public Response() {
}
public List<Vendor> getVendor() {
return vendor;
}
public List<Product> getProducts() {
return products;
}
}
現在,一旦有了JSON字符串,就可以像這樣使用GSON輕松將數據反彈到Response
類中。
Gson gson = new Gson();
Response mResponse = gson.fromJson(jsonString, Response.class);
簡單!
它不在您的第二個for循環中進行,因為您的第一個for循環中存在SomeException
。
您的執行將被拋出到任何catch()
子句中,並且進一步的執行將不會完成,包括您的第二個for循環。
只需嘗試像這樣放置:
JSONObject jsono = new JSONObject(response);
JSONArray children = jsono.getJSONArray("vendor");
JSONArray childrenProducts = jsono.getJSONArray("products");
//this will be executed now..!!
for(int i=0;i<childrenProducts.length();i++){
JSONObject jsonData = childrenProducts.getJSONObject(i);
System.out.println("inside products");
System.out.print(jsonData.getString("name") + "<----dd");
}
for (int i = 0; i <children.length(); i++) {
JSONObject jsonData = children.getJSONObject(i);
System.out.print(jsonData.getString("vendor_name") + "<----");
// String vendorThumbNailURL=jsonData.getString("")
//jvendorImageURL.setImageUrl(local, mImageLoader);
vendorLogo=vendorLogo+jsonData.getString("vendor_logo").trim();
jvendorImageURL.setImageUrl(vendorLogo, mImageLoader);
jvendorName.setText(jsonData.getString("vendor_name"));
jvendorAbout.setText(jsonData.getString("vendor_description"));
jvendorContact.setText(jsonData.getString("contact_number"));
System.out.print(jsonData.getString("products") + "<----");
}
這就是我解決的方法:
try {
JSONObject jsono = new JSONObject(response);
JSONArray children = jsono.getJSONArray("vendor");
for (int i = 0; i <children.length(); i++) {
JSONObject jsonData = children.getJSONObject(i);
System.out.print(jsonData.getString("vendor_name") + "<----");
// String vendorThumbNailURL=jsonData.getString("")
//jvendorImageURL.setImageUrl(local, mImageLoader);
vendorLogo=vendorLogo+jsonData.getString("vendor_logo").trim();
jvendorImageURL.setImageUrl(vendorLogo, mImageLoader);
jvendorName.setText(jsonData.getString("vendor_name"));
jvendorAbout.setText(jsonData.getString("vendor_description"));
jvendorContact.setText(jsonData.getString("contact_number"));
System.out.print(jsonData.getString("products") + "<----");
}
} catch (JSONException e) {
e.printStackTrace();
}
try {
JSONObject jsono = new JSONObject(response);
JSONArray childrenProducts = jsono.getJSONArray("products");
System.out.println(childrenProducts.length()+"LENGTH");
for(int i=0; i<childrenProducts.length(); i++){
JSONObject jsonData1 = childrenProducts.getJSONObject(i);
System.out.println(childrenProducts.length() + "LENGTH");
System.out.print(jsonData1.getString("name") + "<----dd");
}
} catch (JSONException e) {
e.printStackTrace();
}
}
只是必須采取兩個單獨的嘗試塊...有人可以告訴我為什么它在一個嘗試塊中不起作用嗎? 上面的代碼有效
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