[英]MySQL - Update table with row number per group
樣本數據
id | order_id | instalment_num | date_due
---------------------------------------------------------
1 | 10000 | 1 | 2010-07-09 00:00:00
2 | 10000 | 1 | 2010-09-06 11:39:56
3 | 10001 | 1 | 2014-04-25 15:46:52
4 | 10002 | 1 | 2010-01-11 00:00:00
5 | 10003 | 1 | 2010-01-04 00:00:00
6 | 10003 | 1 | 2016-05-31 00:00:00
7 | 10003 | 1 | 2010-01-08 00:00:00
8 | 10003 | 1 | 2010-01-06 09:06:26
9 | 10004 | 1 | 2010-01-11 11:25:07
10 | 10004 | 1 | 2010-01-12 07:06:42
期望的結果
id | order_id | instalment_num | date_due
---------------------------------------------------------
1 | 10000 | 1 | 2010-07-09 00:00:00
2 | 10000 | 2 | 2010-09-06 11:39:56
3 | 10001 | 1 | 2014-04-25 15:46:52
4 | 10002 | 1 | 2010-01-11 00:00:00
5 | 10003 | 1 | 2010-01-04 00:00:00
8 | 10003 | 2 | 2010-01-06 09:06:26
7 | 10003 | 3 | 2010-01-08 00:00:00
6 | 10003 | 4 | 2016-05-31 00:00:00
9 | 10004 | 1 | 2010-01-11 11:25:07
10 | 10004 | 2 | 2010-01-12 07:06:42
如您所見,我有一個instalment_num
列,它應該顯示屬於order_id
的每一行的數量/索引,由date_due ASC, id ASC
順序確定。
如何像這樣更新instalment_num
列?
補充說明
date_due
列不是唯一的,並且可能有許多id
或order_id
具有完全相同的時間戳。
如果屬於同一order_id
兩行的時間戳相同,則它應按id
作為后備順序排序。
我需要一個更新此列的查詢。
我就是這樣做的:
SELECT a.id,
a.order_id,
COUNT(b.id)+1 AS instalment_num,
a.date_due
FROM sample_data a
LEFT JOIN sample_data b ON a.order_id=b.order_id AND (a.date_due>b.date_due OR (a.date_due=b.date_due AND a.id>b.id))
GROUP BY a.id, a.order_id, a.date_due
ORDER BY a.order_id, a.date_due, a.id
更新版本嘗試:
UPDATE sample_data
LEFT JOIN (SELECT a.id,
COUNT(b.id)+1 AS instalment_num
FROM sample_data a
JOIN sample_data b ON a.order_id=b.order_id AND (a.date_due>b.date_due OR (a.date_due=b.date_due AND a.id>b.id))
GROUP BY a.id) c ON c.id=sample_data.id
SET sample_data.instalment_num=c.instalment_num
對於以1開頭的編號:
UPDATE sample_data
LEFT JOIN (SELECT a.id,
COUNT(b.id) AS instalment_num
FROM sample_data a
JOIN sample_data b ON a.order_id = b.order_id AND (a.date_due > b.date_due OR (a.date_due=b.date_due AND a.id + 1 > b.id))
GROUP BY a.id) c ON c.id = sample_data.id
SET sample_data.instalment_num = c.instalment_num
您正在嘗試使用SQL Server或Oracle之類的東西來實現分區的ROW_NUMBER
。 您可以使用適當的查詢來模擬這個:
SELECT t.id, t.order_id,
(
SELECT 1 + COUNT(*)
FROM sampleData
WHERE (date_due < t.date_due OR (date_due = t.date_due AND id < t.id)) AND
order_id = t.order_id
) AS instalment_num,
t.date_due
FROM sampleData t
ORDER BY t.order_id, t.date_due
這個查詢將責令instalment_num
通過due_date
升序排列。 在due_date
中為tie的情況下,它將按id
按升序排序。
請點擊以下鏈接進行演示:
select
sub.order_id, sub.date_due,
@group_rn:= case
when @group_order_id=sub.order_id then @group_rn:=@group_rn:+1
else 1
end as instalment_num,
@group_order_id:=sub.order_id
FROM (select @group_rn:=0, group_order_id=0) init,
(select *
from the_table
order by order_id, date_due) sub
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