我怎樣才能把我的二進制、八進制和十六進制放在一個循環中

Question

所以我這周的目標是找到十六進制的八進制和二進制的十進制。 我能夠獲得十六進制、二進制和八進制，但在不同的公共類中是單獨的循環。 所以我想知道如何使這段代碼合一並在一個循環中讀取十六進制、八進制和二進制。

---

十進制轉十六進制

 import java.util.Scanner;
public class uncode {
public static void main (String[] args) {
    Scanner input = new Scanner(System.in);

    System.out.println("Enter a decimal number: ");
    int decimal = input.nextInt();

    String hex = "";

    while (decimal != 0 ) {
        int hexValue = decimal % 16;

        char hexDigit = (hexValue <= 9 && hexValue > 0) ?
                (char) (hexValue + '0') : (char)(hexValue - 10 + 'A');

                hex = hexDigit + hex;

                decimal = decimal / 16;
        }
    System.out.println("The hex number is " + hex);
    }
}

---

十進制轉八進制

import java.util.Scanner;
public class octal {

    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);
        System.out.println("Enter a decimal number: ");
        int decimal = input.nextInt();
        String octal = "";

        while ( decimal > 0 ) {
            int remainder = decimal % 8;
            octal = remainder + octal;

            decimal = decimal / 8;
        }
        System.out.println("Octal number:  " + octal);
    }

}

---

十進制轉二進制

 import java.util.Scanner;
    public class GuessNumbers {

        public static void main(String[] args) {
            Scanner input = new Scanner(System.in);
            System.out.println("Enter a decimal number: ");
            int decimal = input.nextInt();
            String binary = "";
            while (decimal > 0) {
                int remainder = decimal % 2;
                binary = remainder + binary;
                decimal = decimal / 2;
            }
            System.out.println("Binary number: " + binary);
        }

    }

Answer 1

簡單的方法是使用已經存在的轉換，例如

Scanner input = new Scanner(System.in);
System.out.println("Enter a decimal number: ");
int decimal = input.nextInt();
String hex = Integer.toHexString(decimal);
String oct = Integer.toOctalString(decimal);
String bin = Integer.toBinaryString(decimal);

如果你需要一個整數值，而不是字符串，你可以使用

int h = Integer.parseInt(hex, 16);
int o = Integer.parseInt(oct, 8);
int b = Integer.parseInt(bin, 2);

假設您不想使用這些方法（假設您有自己的理由）。

首先，您需要將代碼放在一個方法中，而不是放在 main 中。

然后你可以做這樣的事情：

public class Class {
    public static void uncode() {
        Scanner input = new Scanner(System.in);

        System.out.println("Enter a decimal number: ");
        int decimal = input.nextInt();

        String hex = "";

        while (decimal != 0) {
            int hexValue = decimal % 16;

            char hexDigit = (hexValue <= 9 && hexValue > 0) ? (char) (hexValue + '0')
                    : (char) (hexValue - 10 + 'A');

            hex = hexDigit + hex;

            decimal = decimal / 16;
        }
        System.out.println("The hex number is " + hex);
    }

    public static void octal() {
        Scanner input = new Scanner(System.in);
        System.out.println("Enter a decimal number: ");
        int decimal = input.nextInt();
        String octal = "";

        while (decimal > 0) {
            int remainder = decimal % 8;
            octal = remainder + octal;

            decimal = decimal / 8;
        }
        System.out.println("Octal number:  " + octal);
    }

    public static void GuessNumbers() {
        Scanner input = new Scanner(System.in);
        System.out.println("Enter a decimal number: ");
        int decimal = input.nextInt();
        String binary = "";
        while (decimal > 0) {
            int remainder = decimal % 2;
            binary = remainder + binary;
            decimal = decimal / 2;
        }
        System.out.println("Binary number: " + binary);
    }

    public static void allInOne() {
        Scanner input = new Scanner(System.in);
        System.out.println("Enter a decimal number: ");
        int decimal = input.nextInt();
        int hex = decimal;
        int oct = decimal;
        int bin = decimal;

        String hexal = "";
        String octal = "";
        String binary = "";

        while (hex > 0 || oct > 0 || bin > 0) {
            if (hex > 0) {
                // Get Hexal
                int hexValue = hex % 16;

                char hexDigit = (hexValue <= 9 && hexValue > 0) ? (char) (hexValue + '0')
                        : (char) (hexValue - 10 + 'A');

                hexal = hexDigit + hexal;

                hex = hex / 16;
            }
            if (oct > 0) {
                // Get Octal
                int remainder = oct % 8;
                octal = remainder + octal;

                oct = oct / 8;
            }
            if (bin > 0) {
                // Get Binary
                int remainder = bin % 2;
                binary = remainder + binary;
                bin = bin / 2;
            }
        }
        System.out.println("The hex number is " + hexal);
        System.out.println("Octal number:  " + octal);
        System.out.println("Binary number: " + binary);
    }

    public static void main(String[] args) {
        uncode();
        octal();
        GuessNumbers();
        allInOne();
    }
}

我試圖對您的代碼進行盡可能少的更改。

Answer 2

在這里，我通過調用方法 getEveryFromDeci(param1,param2) 從十進制轉換為八進制、二進制、十六進制，其中 param1 - 任何十進制數和 param2 - 它的基值，如 8,2,16。 我還通過調用方法 allToDeci(param1,param2) 將八進制、二進制、十六進制轉換為十進制，其中 param1 - 字符串形式的十六進制、二進制、八進制值和 param2- 十六進制的基值

private String getEveryFromDeci(Integer x,Integer y){

    List<String> al = deciBin(x,y,new ArrayList<String>());
    StringBuffer buffer = new StringBuffer();
    for(String s : al)
        buffer.append(s);

    return buffer.toString();

}

private List<String> deciBin(Integer a,Integer b,List<String> list){
    if(a>=b){

        deciBin(a/b,b,list);
        list.add(a%b > 9 ? getHexaDecimal(a%b):Integer.toString(a%b));
    }else
        list.add(Integer.toString(a));

    return list;
}

private String getHexaDecimal(int d){
    String s= null;
    switch(d){
    case 10:
        s="A";
        break;
    case 11:
        s="B";
        break;
    case 12:
        s="C";
        break;
    case 13:
        s="D";
        break;
    case 14:
        s="E";
        break;
    case 15:
        s="F";
        break;
    }

    return s;
}

private int allToDeci(String applyNum,int type){
    int sum =0;
    char[] ch = applyNum.toCharArray();
    for(int pum=0;pum<ch.length;pum++)
        sum += Character.isDigit(ch[pum]) ? getAct(ch.length-(pum+1),type) * Character.getNumericValue(ch[pum]) :getAct(ch.length-(pum+1),type) * getNum(ch[pum]);

    return sum;
}

private int getNum(char ch){
    int num = 0;
    switch(ch){
    case 'A':
        num =10;
        break;
    case 'B':
        num = 11;
        break;
    case 'C':
        num =12;
        break;
    case 'D':
        num =13;
        break;
    case 'E':
        num =14;
        break;
    case 'F':
        num=15;
        break;
        default:
            num =Character.getNumericValue(ch);
            break;
    }

    return num;
}

private int getAct(int k,int p){

    int s=1;
    if(k >0){
        for(int i=0;i<k;i++)
            s *=p;
        return s;
    }else
        return 1;   

}