[英]How To Get JsonArrayRequest JSONArray Response To JSONObject
我從昨天開始就遇到了這個問題,從我的服務器獲取數據。 我在POSTMAN中測試我的PHP代碼並將格式更改為JSON,我甚至在JSONLint上測試它並返回有效的json。 我注意到它返回一個JSONObject
而不是JSONArray
(據我所知JSONArray以[
]開頭。
這是我的java代碼: orgFragment.java
public void parseJSONData(){
RequestQueue requestQueue = Volley.newRequestQueue(getContext());
JsonArrayRequest jsonArray = new JsonArrayRequest(ServerScripts.PHP_SCRIPT_PATH + ServerScripts.PHP_GET_FEEDS, new Response.Listener<JSONArray>() {
@Override
public void onResponse(JSONArray response) {
if (response.length() > 0){
try {
organizationDataList.clear();
for (int i = 0; i < response.length(); i++ ){
JSONObject jsonObject = response.getJSONObject(i);
OrganizationData organizationData = new OrganizationData();
//SQL TABLE NAME
if (!jsonObject.isNull("organizationName")){
organizationData.orgName = jsonObject.getString("organizationName");
}
if (!jsonObject.isNull("organizationType")){
organizationData.orgType = jsonObject.getString("organizationType");
}
if (!jsonObject.isNull("organizationDescription")){
organizationData.orgDesc = jsonObject.getString("organizationDescription");
}
if (!jsonObject.isNull("organizationCategory")){
organizationData.orgCategory = jsonObject.getString("organizationCategory");
}
if (!jsonObject.isNull("organizationCurrentMembers")){
organizationData.orgCurrentMembers = jsonObject.getInt("organizationCurrentMembers");
}
if (!jsonObject.isNull("organizationMaxMembersNo")){
organizationData.orgMaxMembers = jsonObject.getInt("organizationMaxMembersNo");
}
//ADD
organizationDataList.add(organizationData);
}
//NOTIFY
orgListAdapter.notifyDataSetChanged();
}catch (Exception e){
e.printStackTrace();
Toast.makeText(getContext(),e.toString(),Toast.LENGTH_LONG).show();
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
String getErrorMsg = error.toString();
Toast.makeText(getContext(),"Failed to Fetch Data" + getErrorMsg,Toast.LENGTH_LONG).show();
}
});
requestQueue.add(jsonArray);
}
錯誤: 我只是從類型org.json.JSONObject的Logcat成功“}中剪切了json錯誤響應,無法轉換為JSONArray
我只是修改我的PHP代碼,返回一個JSONArray。
//if($_SERVER['REQUEST_METHOD'] == ''){
require('dbConnect.php');
$SQLi_ORG_FEEDS = "SELECT organizationName,organizationDescription,organizationCategory,
organizationCurrentMembers,organizationMaxMembersNo,organizationType FROM org_information";
$query = mysqli_query($dbConnect,$SQLi_ORG_FEEDS) or die("Error".mysqli_error($dbConnect));
$checkRow = mysqli_num_rows($query);
$response = array();
if($checkRow > 0){
while ($getRecord = mysqli_fetch_array($query)) {
$response[] = $getRecord;
/*array_push($response,array(
"organizationName"=>$getRecord['organizationName'],
"organizationDescription"=>$getRecord['organizationDescription'],
"organizationCategory"=>$getRecord['organizationCategory'],
"organizationCurrentMembers"=>$getRecord['organizationCurrentMembers'],
"organizationMaxMembersNo"=>$getRecord['organizationMaxMembersNo'],
"organizationType"=>$getRecord['organizationType']));*/
}
//$response['success'] = 'success';
echo json_encode($response);
//echo json_encode(array("response"=>$response));
}
else {
$response['failed'] = 'failed';
echo json_encode($response);
}
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