jQuery - 如何將一些帶有文本的標記元素移動到最近的div中

Question

我有以下HTML結構：

<span class="green_box">
    <div class="icheckbox_flat-red_green" style="position: relative;">
        <input type="radio" name="minimal-radio" data-cid="5" data-uid="10" data-sid="1" data-pid="1" value="1" style="position: absolute; opacity: 0;">
        <ins class="iCheck-helper" style="position: absolute; top: 0%; left: 0%; display: block; width: 100%; height: 100%; margin: 0px; padding: 0px; border: 0px; opacity: 0; background: rgb(255, 255, 255);"></ins>
    </div>
    <i class="">1</i>
</span>
<span class="green_box">
    <div class="icheckbox_flat-red_green" style="position: relative;">
        <input type="radio" name="minimal-radio" data-cid="5" data-uid="10" data-sid="1" data-pid="1" value="1" style="position: absolute; opacity: 0;">
        <ins class="iCheck-helper" style="position: absolute; top: 0%; left: 0%; display: block; width: 100%; height: 100%; margin: 0px; padding: 0px; border: 0px; opacity: 0; background: rgb(255, 255, 255);"></ins>
    </div>
    <i class="">2</i>
</span>
<span class="green_box">
    <div class="icheckbox_flat-red_green" style="position: relative;">
        <input type="radio" name="minimal-radio" data-cid="5" data-uid="10" data-sid="1" data-pid="1" value="1" style="position: absolute; opacity: 0;">
        <ins class="iCheck-helper" style="position: absolute; top: 0%; left: 0%; display: block; width: 100%; height: 100%; margin: 0px; padding: 0px; border: 0px; opacity: 0; background: rgb(255, 255, 255);"></ins>
    </div>
    <i class="">3</i>
</span>

現在我想在<div>..</div>標簽內移動<i>..</i>標簽，如：

<span class="green_box">
    <div class="icheckbox_flat-red_green" style="position: relative;">
        <input type="radio" name="minimal-radio" data-cid="5" data-uid="10" data-sid="1" data-pid="1" value="1" style="position: absolute; opacity: 0;">
        <ins class="iCheck-helper" style="position: absolute; top: 0%; left: 0%; display: block; width: 100%; height: 100%; margin: 0px; padding: 0px; border: 0px; opacity: 0; background: rgb(255, 255, 255);"></ins>
        <i class="">1</i>
    </div>    
</span>
<span class="green_box">
    <div class="icheckbox_flat-red_green" style="position: relative;">
        <input type="radio" name="minimal-radio" data-cid="5" data-uid="10" data-sid="1" data-pid="1" value="1" style="position: absolute; opacity: 0;">
        <ins class="iCheck-helper" style="position: absolute; top: 0%; left: 0%; display: block; width: 100%; height: 100%; margin: 0px; padding: 0px; border: 0px; opacity: 0; background: rgb(255, 255, 255);"></ins>
        <i class="">2</i>
    </div>    
</span>
<span class="green_box">
    <div class="icheckbox_flat-red_green" style="position: relative;">
        <input type="radio" name="minimal-radio" data-cid="5" data-uid="10" data-sid="1" data-pid="1" value="1" style="position: absolute; opacity: 0;">
        <ins class="iCheck-helper" style="position: absolute; top: 0%; left: 0%; display: block; width: 100%; height: 100%; margin: 0px; padding: 0px; border: 0px; opacity: 0; background: rgb(255, 255, 255);"></ins>
        <i class="">3</i>
    </div>
</span>

我試過像jQuery一樣：

$('.green_box i').appendTo('.green_box div');

但沒有工作。 任何想法如何移動<i>..</i>標簽與最近的<div>..</div>元素。

我的JSFiddle： https ：//jsfiddle.net/47htz1yb/

謝謝

Answer 1

您可以使用each()方法執行此工作。

 $(".green_box").each(function(){ $(this).find(".icheckbox_flat-red_green").append($(this).find("i")); }); 

 .icheckbox_flat-red_green > i { color: red; } 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <span class="green_box"> <div class="icheckbox_flat-red_green"> <input type="radio" name="minimal-radio"> <ins class="iCheck-helper"></ins> </div> <i class="">1</i> </span> <span class="green_box"> <div class="icheckbox_flat-red_green"> <input type="radio" name="minimal-radio"> <ins class="iCheck-helper"></ins> </div> <i class="">2</i> </span> <span class="green_box"> <div class="icheckbox_flat-red_green"> <input type="radio" name="minimal-radio"> <ins class="iCheck-helper"></ins> </div> <i class="">3</i> </span> 

使用上面的CSS， icheckbox_flat-red_green類中的每個i元素icheckbox_flat-red_green red 。

Answer 2

試試這個： https ： //jsfiddle.net/47htz1yb/3/

$('.green_box i').each(function(index, icon) {
    $(icon).siblings('div').append(icon)
})

問題$('.green_box i').appendTo('.green_box div'); 是它將基本上采取所有i元素並將其放在第一個.green_box div 。

你需要的是循環遍歷所有i元素，找到兄弟div並將i追加到那里。

Answer 3

試試這個：

$('.green_box i').each(function(){ 
    var $this = $(this),
        $prev = $this.prev(),
        $i = $this.remove();

    $prev.append($i);
});

Answer 4

$('.green_box i').each(function (i) {
    $('.green_box div').eq(i).append($(this));
});