[英]Append element to each div in order
好吧,我正在嘗試使用css
和html
制作徽標,這是輸出:
現在我想用jquery
並動態創建所有div
。 到目前為止,這是我所做的:
var count = 13;
var n = 0;
for(var i = 0; i < count; i++) {
n++;
$('<div class="LogoRow" id="LogoRow-'+n+'"></div>').appendTo('#Logo');
}
$('#Logo .LogoRow:nth-child(odd)').addClass('LogoRowLeft');
$('#Logo .LogoRow:nth-child(even)').addClass('LogoRowRight');
$('.LogoRow').each(function() {
var count = 8;
for(var i = 0; i < count; i++) {
$(this).append('<span class="LogoTriangle"></span>');
}
});
我在#Logo
后面附加了13 LogoRow
,然后在每個LogoRow
后面附加了8 LogoTriangle
,但是問題是它應該LogoTriangle
不同的方式附加LogoTriangle
,如下所示:
append 8 `LogoTriangle` to `LogoRow` nth child 1
append 7 `LogoTriangle` to `LogoRow` nth child 2 and 3
append 6 `LogoTriangle` to `LogoRow` nth child 4 and 5
append 5 `LogoTriangle` to `LogoRow` nth child 6 and 7
append 4 `LogoTriangle` to `LogoRow` nth child 8 and 9
append 3 `LogoTriangle` to `LogoRow` nth child 10 and 11
append 2 `LogoTriangle` to `LogoRow` nth child 12 and 13
append 1 `LogoTriangle` to `LogoRow` nth child 14 and 15
但我不知道如何將元素附加到這樣的另一個元素。 有什么建議嗎?
將初始count
設置為15
,以獲得完整的三角形。
將count = 8
移到循環外,並更改條件以減小該值,如下所示。
count = 8;
$('.LogoRow').each(function(k) {
console.log(count);
for (var i = 0; i < count; i++) {
$(this).append('<span class="LogoTriangle"></span>');
}
if (k == 0 || (k > 0 && k % 2 == 0))
count--;
});
或者,您可以通過不是那么簡單但易於理解的方式來做到這一點:
var count = 15;
var n = 0;
for(var i = 0; i < count; i++){
n++;
$('<div class="LogoRow" id="LogoRow-'+n+'"></div>').appendTo('#Logo');
}
$('#Logo .LogoRow:nth-child(odd)').addClass('LogoRowLeft');
$('#Logo .LogoRow:nth-child(even)').addClass('LogoRowRight');
var appends = {
1: 8, 2: 7, 3: 7, 4: 6, 5: 6, 6: 5, 7: 5,
8: 4, 9: 4, 10: 3, 11: 3, 12: 2, 13: 2,
14: 1, 15: 1,
};
for(var i in appends){
if(appends.hasOwnProperty(i)){
console.log(i, appends[i]);
for(var j = 0; j < appends[i]; j++){
$('#LogoRow-' + i).append('<span class="LogoTriangle"></span>');
}
}
}
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