變量無法訪問PHP函數中的內部查詢

Question

我使用ajax傳遞了一個變量以在我的php文件“ Cart_code.php”中運行。 為什么變量不能在函數內部訪問？

Java腳本

$.ajax({
    type: "POST",
    url: "includes/Cart_code.php",
    data: {ID:id},
    success: function(result){
        console.log(result);
    }

});
     });

});
</script>

Cart_code.php

function cart_head_info_print()
{
    if(isset($_POST['ID']))
    { 
        //Here the id is accessing. To make it accessible inside query, i made it global 
        echo $GLOBALS['pro_id'] = $_POST['ID'];
    }

    parent::db();
    $email = $_SESSION['email'];
    $pro_id =  $GLOBALS['pro_id'];

    $query = "SELECT product_name , product_description from cart WHERE u_email = '$email' and product_id = '$pro_id'";
}

Answer 1

    function cart_head_info_print(){
      //this is for debugging. If this is empty/null/etc then you have a problem

      var_dump($_POST['ID']);          


     //$_POST is a super global so you don't need to do anything special

                parent::db();
                $email = $_SESSION['email'];
                $pro_id =  $POST['ID'];

                $query = "SELECT product_name , product_description from cart WHERE u_email = '$email' and product_id = '$pro_id'";
    }
// if you truly are missing the function call then you need this too, but I don't think you're missing this
cart_head_info_print();

更新1

http://php.net/manual/zh/keyword.parent.php

我很肯定您使用的是parent::錯誤。 我將其刪除。