在圖的struct中聲明的函數指針，分配相同的函數
[英]Function pointer declared in struct for graph, assign same function
問題描述
基本上我不能使這個邏輯模擬器起作用！ 我制作了一個鄰接表，將所有門相互連接，然后為它們分配一個值，作為負責人的AdjList應該使用功能指針計算該值。 問題是它調用的唯一函數是And！（永遠不會調用Xor Nand等。）特定點是初始化指針的地方
struct AdjList
{
struct AdjListNode *head;
string GateName;
string OutputName;
bool result;
function <bool (vector <bool>)> ptrf;
};
和他們被分配
if(i < Gate_IO.size() )
{
ptrPos = Gate_IO[i].find_first_of(' ');
switch (strtoi ( (Gate_IO[i].substr(0,ptrPos).c_str() )))
{
case strtoi("AND"):
{
VectorHeadPtr[i].ptrf = And;
break;
}
case strtoi("NAND"):
{
VectorHeadPtr[i].ptrf = Nand;
break;
}
case strtoi("OR"):
{
VectorHeadPtr[i].ptrf = Or;
break;
}
case strtoi("NOR"):
{
VectorHeadPtr[i].ptrf = Nor;
break;
}
case strtoi("XOR"):
{
VectorHeadPtr[i].ptrf = Xor;
break;
}
default:
break;
}
然后在CalcGateValue（）函數中調用它們以執行程序！ 似乎他們被識別並在VectorHeadPtr [i] .ptrf中分配了正確的值，我試圖在這一點退出，並進入該周期，但是當我調用CalcGateValue（）時調用的唯一函數是And！ 我想念什么嗎？ 這是完整的代碼：
#include <iostream>
#include <cstdlib>
#include <string>
#include <sstream>
#include <vector>
#include <algorithm>
#include <functional>
using namespace std;
int compare(string a, string b)
{
int n = count(a.begin(), a.end(), 'I');
int q = count(b.begin(), b.end(), 'I');
return n > q;
}
constexpr unsigned int strtoi(const char* str, int h = 0) //string to int for switch cycle
{
return !str[h] ? 5381:(strtoi(str, h+1)*33)^str[h];
}
bool Xor(vector<bool> inputs)
{ cout<<"Xor function called!"<<endl;
int counter = 0;
for (unsigned int i = 0;i < inputs.size(); i++)
{
if (inputs.at(i) == 1)
{
counter++;
}
}
if (counter % 2) //Xor gate gives output 1 if and odd number of 1 inputs is given
{
return 1;
}
else
{
return 0;
}
}
bool And(vector<bool> inputs) //static per richiamare la funzione dalla classe
{ cout<<"And function called!"<<endl;
for (int i = 0; i < (inputs.size()-1); i++)
{
if(inputs.at(i) == 0)
{
return 0;
}
}
return 1;
}
bool Nand(vector<bool> inputs)
{ cout<<"Nand function called!"<<endl;
return !And(inputs);
}
bool Or(vector<bool> inputs)
{cout<<"Or function called!"<<endl;
for (int i = 0; i < (inputs.size()-1); i++)
{
if (inputs.at(i) != inputs.at(i+1) )
{
return 1;
}
}
return inputs.at(0);//Any position it's ok because all nPoss are the same.
}
bool Nor(vector<bool> inputs)
{ cout<<"Nor function called!"<<endl;
return !Or(inputs);
}
/*
* Adjacency list node
*/
struct AdjListNode
{
int nPos;
bool gValue;
string name;
struct AdjListNode* next;
};
/*
* Adjacency list
*/
struct AdjList
{
struct AdjListNode *head;
string GateName;
string OutputName;
bool result;
function <bool (vector <bool>)> ptrf;
};
/**
* Class Graph
*/
class Graph
{
private:
int V;
int circInputs = 3;
int circOutputs = 2;
int circGates;
int PrimaryInputs = 0;
vector<string> ioPuts;
struct AdjList* VectorHeadPtr;
public:
Graph(vector<string> Gate_IO)
{
int ptrPos,cntr;
int cntrIO = 0;
int prevPrimaryInputs = 0;
bool flag_remove_duplicates = 0;
string GateToConnect;
circGates = Gate_IO.size();
V=Gate_IO.size() + circInputs + circOutputs; //n°gates+input+output letti dal file
sort (Gate_IO.begin(), Gate_IO.end(), compare);
for (cntr = 0; cntr < (Gate_IO.size()-1) && (PrimaryInputs == prevPrimaryInputs); cntr++)
{
PrimaryInputs = count (Gate_IO[cntr+1].begin(), Gate_IO[cntr+1].end(), 'I');
prevPrimaryInputs = count (Gate_IO[cntr].begin(), Gate_IO[cntr].end(), 'I');
}
PrimaryInputs = cntr; //Here starts first N
for (int i = 0;i<Gate_IO.size();i++)
VectorHeadPtr = new AdjList [V];
for (int i = 0; i < V; i++)
{
if(i < Gate_IO.size() )
{
ptrPos = Gate_IO[i].find_first_of(' ');
switch (strtoi ( (Gate_IO[i].substr(0,ptrPos).c_str() )))
{
case strtoi("AND"):
{
VectorHeadPtr[i].ptrf = And;
break;
}
case strtoi("NAND"):
{
VectorHeadPtr[i].ptrf = Nand;
break;
}
case strtoi("OR"):
{
VectorHeadPtr[i].ptrf = Or;
break;
}
case strtoi("NOR"):
{
VectorHeadPtr[i].ptrf = Nor;
break;
}
case strtoi("XOR"):
{
VectorHeadPtr[i].ptrf = Xor;
break;
}
default:
break;
}
VectorHeadPtr[i].head = NULL;
stringstream ss;
ss << Gate_IO[i];
for (string temp; ss >> temp;)
{
if ( (temp.at(0)=='I') || (temp.at(0)=='O') && (temp!="OR") )
{
ioPuts.push_back(temp);
}
else if (temp.at(0) == 'U')
{
VectorHeadPtr[i].GateName=temp;
}
}
ptrPos = Gate_IO[i].find_last_of(' ');
VectorHeadPtr[i].OutputName = Gate_IO[i].substr(ptrPos);
}
else
{
if (flag_remove_duplicates == 0)
{
sort (ioPuts.begin(), ioPuts.end() );
ioPuts.erase (unique (ioPuts.begin(), ioPuts.end() ), ioPuts.end() );
flag_remove_duplicates = 1;
}
VectorHeadPtr[i].head = NULL;
VectorHeadPtr[i].ptrf = NULL;
VectorHeadPtr[i].GateName = ioPuts[cntrIO];
cntrIO++;
}
}
for (int i = 0; i < Gate_IO.size(); i++)
{
for(int j = 0; j < 2; j++)
{
ptrPos = Gate_IO[i].find_first_of(' ')+1;
Gate_IO[i].erase (0,ptrPos);
}
ptrPos = Gate_IO[i].find_last_of(' ')+1;
Gate_IO[i].erase( ptrPos);
stringstream ss;
ss << Gate_IO[i];
ss >> GateToConnect;
for (string temp; ss >> temp;)
{
addEdge(GateToConnect,temp);
}
}
}
/**
* Creates new adjacency list node for addEdge function
*/
AdjListNode* newAdjListNode(int nPos, string Name)
{
AdjListNode* newNode = new AdjListNode;
newNode->nPos = nPos;
newNode->name = Name;
newNode->next = NULL;
return newNode;
}
/**
* Add edge to graph
*/
void addEdge(string source, string destination)
{
int from, to;
for (int i = 0; i < V; ++i)
{
if ( (source == VectorHeadPtr[i].GateName) || (source == VectorHeadPtr[i].OutputName) )
{
from = i;
}
else if (( destination == VectorHeadPtr[i].GateName) || (destination == VectorHeadPtr[i].OutputName) )
{
to = i;
}
}
AdjListNode* newNode = newAdjListNode(to, destination);
newNode->next = VectorHeadPtr[from].head;
VectorHeadPtr[from].head = newNode;
}
/*
* Print the graph
*/
void printGraph()
{
for (int i = 0; i < circGates; i++)//meno ooutput+input
{
AdjListNode* Ptr = VectorHeadPtr[i].head;
cout<<endl<<"Gate connections for "<<VectorHeadPtr[i].GateName;
while (Ptr)
{
cout <<"-> "<< Ptr->name;
Ptr = Ptr->next;
}
cout<<" Output name is:"<<VectorHeadPtr[i].OutputName<<endl;
}
}
void calcGateVal()
{
vector<bool> Val={0, 1, 0};
vector<bool> Op;
for (int i = 0; i < circOutputs; i++)
{
ioPuts.pop_back();
}
for (int i = 0; i < circGates; i++)
{
AdjListNode* Ptr = VectorHeadPtr[i].head;
while (Ptr)
{
if (Ptr->name.at(0) == 'I')
{
for (int j = 0; j < ioPuts.size(); j++)
{
if (Ptr->name == ioPuts[j])
{
Ptr->gValue = Val[j];
}
}
}
Ptr = Ptr->next;
}
}
for (int i = 0; i < PrimaryInputs; i++)
{
AdjListNode* Ptr = VectorHeadPtr[i].head;
while (Ptr)
{
Op.push_back(Ptr->gValue);
Ptr = Ptr->next;
}
VectorHeadPtr[i].result = VectorHeadPtr[i].ptrf(Op);
cout<<"Gate Value is: "<<VectorHeadPtr[i].result<<" OutputName: "<<VectorHeadPtr[i].OutputName<<" GateName: "<<VectorHeadPtr[i].GateName<<endl;
Op.clear();
}
for (int i = PrimaryInputs; i < V; i++)
{
AdjListNode* Ptr = VectorHeadPtr[i].head;
while (Ptr)
{
for (int j = 0; j < PrimaryInputs; j++)
{
if (Ptr->name == VectorHeadPtr[j].OutputName)
{
Ptr->gValue = VectorHeadPtr[j].result;
}
}
Ptr = Ptr->next;
}
}
for (int i = PrimaryInputs; i < circGates; i++)
{
AdjListNode* Ptr = VectorHeadPtr[i].head;
while (Ptr)
{
Op.push_back(Ptr->gValue);
Ptr = Ptr->next;
}
VectorHeadPtr[i].result = VectorHeadPtr->ptrf(Op);
Op.clear();
}
}
void displayOutput()
{ cout<<endl;
for (int i = 0; i < circGates; i++)
{
cout<<"Value of outputs are ("<<VectorHeadPtr[i].GateName<<") "<<VectorHeadPtr[i].OutputName<<": "<<VectorHeadPtr[i].result<<endl;
}
}
};
/*
* Main
*/
int main()
{
vector<string> G_d;
G_d.push_back("AND 2 U0 I0 I1 N0");
G_d.push_back("XOR 2 U1 N0 I2 O0");
G_d.push_back("AND 2 U2 N0 I2 N1");
G_d.push_back("AND 2 U3 I0 I1 N2");
G_d.push_back("OR 2 U4 N1 N2 O1");
Graph gh(G_d);
gh.calcGateVal();
gh.displayOutput();
gh.printGraph();
// print the adjacency list representation of the above graph
return 0;
}
1 個解決方案
解決方案1
0 2016-06-21 10:19:06
我認為您的代碼無法產生您所說的結果。 請看這里：
為什么要通過大小寫比較將字符串轉換為帶有strtoi的整數？ ：
大小寫strtoi（“ NAND”）：
- 更好的方法是將strcmp或將每個字符串存儲在一個字符串中，或者將其存儲在一個查找表中，並執行“ ==相等相等”比較，這對於字符串來說是重載的。
考慮通過引用而不是值傳遞向量和對象，您可能期望對象返回一個值，但是由於通過值傳遞，您永遠看不到它們，這也避免了復制向量的開銷。
如何將結構函數指針分配給結構函數
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