[英]SQL Server SUM of values in column counted 3 different ways in the same output
我試圖找到正確的方法來編寫查詢以獲取以下數據集:
CustName CityID TransactionCount Complete InProc
Hammertown 10001 200 50 150
SportsAuth 10002 10 1 9
“完成”是較小的TransactionCount集,當未顯示的另一列(格式)等於:時,它應該是TransactionCount的總和:
having [format]=23
or [format]=25
or [format]=38
or [format]>=400 and [format]<=499
or [format]>=800 and [format]<=899
然后,“ InProc”應該是TransactionCount值的其余部分。 到目前為止,我已經提出了以下建議:
SELECT c.CustName,
t.[City],
sum (t.[TransactionCount]) as InProc
FROM [log].[dbo].[TransactionSummary] t
JOIN [log].[dbo].[Customer] c
on t.CustNo = c.CustNo
and t.City = c.City
and t.subno = c.subno
where t.transactiondate between '6/1/16' and '6/22/16'
group by c.CustName,t.City,t.TransactionCount,[format]
having [format]=23
or [format]=25
or [format]=38
or [format]>=400 and [format]<=499
or [format]>=800 and [format]<=899
當前將輸出以下數據:
CustName CityID InProc
Hammertown 10001 147
Hammertown 10001 1
Hammertown 10001 1
Hammertown 10001 1
SportsAuth 10002 4
SportsAuth 10002 4
SportsAuth 10002 1
因此,不僅我沒有為每個客戶獲得1個結果,而且我不知道如何在不破壞此查詢的情況下添加其他2列。 我能得到的任何幫助將不勝感激。
假設您可以通過CustName和CityID獲得兩個子集(您的示例不清楚)。 一個簡單的連接可以將它們組合在一起。 在下面的示例中。 別名A將是主要摘要,別名B將是正在進行中
Select A.CustName
,A.CityID
,A.TransactionCount
,Complete = A.TransactionCount - isnull(B.InProc,0)
.InProc = isnull(B.InProc,0)
From (Select CustName,CityID,TransactionCount=sum(Transactions) From SomeTable Group By CustName,CityID) A
Left Join (Select CustName,CityID,InProc=sum(InProc) From SomeOtherTable Group By CustName,CityID) B
Order By A.CustName,,A.CityID
SELECT sq.*, sq.TransactionCountTotal - sq.CompleteTotal as InProcTotal from
(
select
c.CustName,
t.[City],
sum (t.TransactionCount) as TransactionCountTotal
sum (
case
when (
[format] in (23,25,38)
or [format] between 400 and 499
or format between 800 and 899
)
then t.TransactionCount
else 0
end
) as CompleteTotal
FROM [log].[dbo].[TransactionSummary] t
INNER JOIN [log].[dbo].[Customer] c
on t.CustNo = c.CustNo
and t.City = c.City
and t.subno = c.subno
where t.transactiondate between '6/1/16' and '6/22/16'
group by c.CustName,t.City
) sq
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