Mysqli語句：空白結果

Question

需要我的mysqli語句的幫助。 我在頁面上沒有任何錯誤，但是我的if語句也沒有打印出任何內容。

//$dbConnection works.

$extensionAdd_query_domain_extension = mysqli_query($dbConnection, "
    SELECT * 
    FROM domain 
    WHERE extensions='$extensionAdd_extension' 
    LIMIT 1");
$extensionAdd_query_domain_row = mysqli_fetch_array($extensionAdd_query_domain_extension, MYSQLI_NUM);
$extensionAdd_query_domain_id = sanitizeInt($extensionAdd_query_domain_row[0],$dbConnection);
$extensionAdd_query_domain_votes = sanitizeInt($extensionAdd_query_domain_row[2],$dbConnection);

//If domain id found in Db update votes otherwise add to list
if($extensionAdd_query_domain_id!='' && $extensionAdd_query_domain_votes!='')
    {
        echo 'Found in DB. Update Votes.'.$extensionAdd_extension;
    }
else
    {
        echo 'Not Found in DB. Enter in DB'.$extensionAdd_extension;
    }

Answer 1

檢查數據庫的連接，並使用var_dump檢查結果。

/* check connection */
if (mysqli_connect_errno()) {
    printf("Connect failed: %s\n", mysqli_connect_error());
    exit();
}

var_dump($extensionAdd_query_domain_row);