[英]Draw an ASCII diamond in a frame
我想在一個框架中畫出一顆鑽石。 我想通了上半場的方法,但是當我來到下半場時,我試圖反轉循環並且出現了問題。 我嘗試切換運算符只是為了查看結果,但仍然沒有任何效果。 請幫忙。 什么我沒看到。
// 1st Half of Diamond
// Creates Lines
for (int i = 1; i <= 3; i++) {
if (i == 1) {
System.out.print("+");
for (int h = 1; h <= 8; h++) {
System.out.print("-");
}
System.out.print("+" + "\n");
}
System.out.print("|");
// Nested Loop Creates Spaces Left Side
for (int j = 4; j > i; j--) {
System.out.print(" ");
}
System.out.print("/");
// Nested Loop Creates Values Inside
for (int j = 1; j < i; j++) {
if (i % 2 == 0) {
System.out.print("--");
} else if (i == 1) {
System.out.print("\\");
} else {
System.out.print("==");
}
}
System.out.print("\\");
// Nested Loop Creates Spaces Right Side
for (int j = 4; j > i; j--) {
System.out.print(" ");
}
System.out.print("|");
System.out.print("\n");
}
// Midpoint of Diamond
System.out.print("|<------>|" + "\n");
//============================
//****HERE PROBLEMS ARISE****
// 2nd Half of Diamond
// Creates Lines
for (int i = 1; i <= 3; i++) {
System.out.print("|");
// Nested Loop Creates Spaces Left Side
for (int j = 1; j <= i; j++) {
System.out.print(" ");
}
System.out.println("\\");
// Nested Loop Creates Values Inside
for (int j = 1; j < 2; j++) {
System.out.print("+");
for (int h = 1; h <= 8; h++) {
System.out.print("-");
}
System.out.print("+" + "\n");
if (i % 2 == 0) {
System.out.print("-");
} else if (i == 3) {
System.out.print("/");
} else {
System.out.print("=");
}
}
}
我假設您正在嘗試實現此結果:
public class Diamond {
public static void main(String[] args) {
// 1st Half of Diamond
// Creates Lines
for (int i = 1; i <= 3; i++) {
if (i == 1) {
System.out.print("+");
for (int h = 1; h <= 8; h++) {
System.out.print("-");
}
System.out.print("+" + "\n");
}
System.out.print("|");
// Nested Loop Creates Spaces Left Side
for (int j = 4; j > i; j--) {
System.out.print(" ");
}
System.out.print("/");
// Nested Loop Creates Values Inside
for (int j = 1; j < i; j++) {
if (i % 2 == 0) {
System.out.print("--");
} else if (i == 1) {
System.out.print("\\");
} else {
System.out.print("==");
}
}
System.out.print("\\");
// Nested Loop Creates Spaces Right Side
for (int j = 4; j > i; j--) {
System.out.print(" ");
}
System.out.print("|");
System.out.print("\n");
}
// Midpoint of Diamond
System.out.print("|<------>|" + "\n");
// 2nd Half of Diamond
// Creates Lines
for (int i = 1; i <= 3; i++) {
System.out.print("|");
// Nested Loop Creates Spaces Left Side
for (int j = 1; j <= i; j++) {
System.out.print(" ");
}
System.out.print("\\");
// Nested Loop Creates Values Inside
for (int j = 1; j <= i; j++) {
if (i == 2) {
System.out.print("-");
} else if (i == 1) {
System.out.print("====");
} else {
System.out.print("");
}
}
System.out.print("/");
// Nested Loop Creates Spaces Right Side
for (int j = 0; j < i; j++) {
System.out.print(" ");
}
System.out.println("|");
}
System.out.print("+");
for (int h = 1; h <= 8; h++) {
System.out.print("-");
}
System.out.print("+" + "\n");
}
}
輸出:
+--------+
| /\ |
| /--\ |
| /====\ |
|<------>|
| \====/ |
| \--/ |
| \/ |
+--------+
首先,我建議將您的代碼按照輸出整齊地分組。 當你沒有輸出時,很難看到哪些代碼塊產生了什么。 這是第一部分的清理版本(但代碼完全相同):
// 1st Half of Diamond
for (int i = 1; i <= 3; i++) {
//TOP OR BOTTOM LINE
{
if (i == 1) {
System.out.print("+");
for (int h = 1; h <= 8; h++) {
System.out.print("-");
}
System.out.print("+" + "\n");
}
}
//INTERIOR LINES
{
System.out.print("|");
// Nested Loop Creates Spaces Left Side
for (int j = 4; j > i; j--) {
System.out.print(" ");
}
System.out.print("/");
// Nested Loop Creates Values Inside
for (int j = 1; j < i; j++) {
if (i % 2 == 0) {
System.out.print("--");
} else if (i == 1) {
System.out.print("\\");
} else {
System.out.print("==");
}
}
System.out.print("\\");
// Nested Loop Creates Spaces Right Side
for (int j = 4; j > i; j--) {
System.out.print(" ");
}
System.out.print("|");
System.out.print("\n");
}
}
輸出是你得到的
+--------+
| /\ |
| /--\ |
| /====\ |
反轉 for 循環通常與反轉索引一樣簡單,因此您將外部循環更改為for (int i = 3; i >=1; i--)
,它給出的輸出為:
| /====\ |
| /--\ |
+--------+
| /\ |
您會注意到最后一行打印得較早,因此您應該將\\\\TOP OR BOTTOM LINE
塊與\\\\INTERIOR LINES
塊切換,它輸出:
| /====\ |
| /--\ |
| /\ |
+--------+
現在你只需要切換你的反斜杠和正斜杠。 結果代碼打印了一個不錯的下半部分:
| \====/ |
| \--/ |
| \/ |
+--------+
代碼是:
// 2nd Half of Diamond
for (int i = 3; i >= 1; i--) {
//INTERIOR LINES
{
System.out.print("|");
// Nested Loop Creates Spaces Left Side
for (int j = 4; j > i; j--) {
System.out.print(" ");
}
System.out.print("\\");
// Nested Loop Creates Values Inside
for (int j = 1; j < i; j++) {
if (i % 2 == 0) {
System.out.print("--");
} else if (i == 1) {
System.out.print("/");
} else {
System.out.print("==");
}
}
System.out.print("/");
// Nested Loop Creates Spaces Right Side
for (int j = 4; j > i; j--) {
System.out.print(" ");
}
System.out.print("|");
System.out.print("\n");
}
//TOP OR BOTTOM LINE
{
if (i == 1) {
System.out.print("+");
for (int h = 1; h <= 8; h++) {
System.out.print("-");
}
System.out.print("+" + "\n");
}
}
}
從-n
到n
兩個嵌套for 循環和幾個if else 語句。 零點位於菱形的中心。
public static void main(String[] args) {
printDiamond(5);
}
static void printDiamond(int n) {
System.out.println("n=" + n);
// vertical axis
for (int i = -n; i <= n; i++) {
// horizontal axis
for (int j = -n - 1; j <= n + 1; j++)
if (j == 0) continue; // skip middle vertical
else if (Math.abs(j) == n + 1) // vertical borders & corners
System.out.print(Math.abs(i) == n ? "+" : "|");
else if (Math.abs(i) == n) // horizontal borders
System.out.print("-");
else if (i == 0 && Math.abs(j) == n) // middle left & right tips
System.out.print(j == -n ? "<" : ">");
else if (Math.abs(i - j) == n) // upper right & lower left edges
System.out.print("\\");
else if (Math.abs(i + j) == n) // upper left & lower right edges
System.out.print("/");
else if (Math.abs(i) + Math.abs(j) < n) // inner rhombus lines
System.out.print((n - i) % 2 != 0 ? "=" : "-");
else // whitespace
System.out.print(" ");
System.out.println(); // new line
}
}
輸出:
n=5
+----------+
| /\ |
| /--\ |
| /====\ |
| /------\ |
|<========>|
| \------/ |
| \====/ |
| \--/ |
| \/ |
+----------+
另請參閱:如何打印帶框架的鑽石?
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