[英]Why does only one JavaScript function execute onClick?
我對JavaScript有點陌生,也就是說我在代碼中遇到了一個奇怪的錯誤。 我的HTML中有3張圖片,當單擊它們時應以模式打開。 由於某種原因,模態將卡在新圖像的最后一個圖像上。 例如,如果我單擊第一個,然后單擊第三個,然后單擊第二個,無論我在第二個顯示器上單擊什么圖像。 我嘗試通過將H1標簽替換為圖像名稱來進行調試,這又引發了另一條曲線,因為現在需要兩次單擊才能執行模態。 我不確定自己在做什么,我們將不勝感激。
JS-
<script>
function mode(param)
{
smode = param;
document.getElementById("h1thing").innerHTML = smode;
document.getElementById("myImage").src = smode;
run();
}
function run(){
// Get the modal
var modal = document.getElementById('myModal');
// Get the button that opens the modal
var btn = document.getElementById(smode);
// Get the <span> element that closes the modal
var span = document.getElementsByClassName("close")[0];
// When the user clicks the button, open the modal
btn.onclick = function() {
modal.style.display = "block";
}
// When the user clicks on <span> (x), close the modal
span.onclick = function() {
modal.style.display = "none";
smode = "";
}
// When the user clicks anywhere outside of the modal, close it
window.onclick = function(event) {
if (event.target == modal) {
modal.style.display = "none";
smode = "";
}
}
}
</script>
HTML-
<body>
<h2 id="h1thing">Modal Example</h2>
<!-- Trigger/Open The Modal -->
<center>
<div class="floated_img">
<input id="ScreenShot.png" type="image" src="ScreenShot.png" width="400" height="300" alt="ScreenShot" onclick="myFunction();mode('ScreenShot.png');">
</input>
</div>
<div class="floated_img">
<input id="ScreenShot2.png" type="image" src="ScreenShot2.png" width="400" height="300" alt="ScreenShot2" onclick="myFunction();mode('ScreenShot2.png');">
</input>
</div>
<div class="floated_img">
<input id="kimlexi.jpg" type="image" src="kimlexi.jpg" width="400" height="300" alt="Kimlexi" onclick="myFunction();mode('kimlexi.jpg');">
</input>
</div>
</center>
<!-- The Modal -->
<div id="myModal" class="modal">
<!-- Modal content -->
<div class="modal-content">
<span class="close">
<img src="x.png" width="40" height="40" alt="X">
</span>
<center>
<img id="myImage" src="" width="600" height="500" alt="Kimlexi">
</center>
</div>
</div>
</body>
CSS-
<style>
button {
background:transparent;
border:none;
outline:none;
display:block;
height:200px;
width:200px;
cursor:pointer;
}
/* The Modal (background) */
.modal {
display: none; /* Hidden by default */
position: fixed; /* Stay in place */
z-index: 1; /* Sit on top */
padding-top: 100px; /* Location of the box */
left: 0;
top: 0;
width: 100%; /* Full width */
height: 100%; /* Full height */
overflow: auto; /* Enable scroll if needed */
background-color: rgb(0,0,0); /* Fallback color */
background-color: rgba(0,0,0,0.4); /* Black w/ opacity */
}
/* Modal Content */
.modal-content {
background-color: #fefefe;
margin: auto;
padding: 20px;
border: 1px solid #888;
width: 80%;
}
/* The Close Button */
.close {
color: #aaaaaa;
float: right;
font-size: 28px;
font-weight: bold;
}
.close:hover,
.close:focus {
color: #000;
text-decoration: none;
cursor: pointer;
}
.floated_img
{
float: left;
}
</style>
這里有兩個問題。
mode('ScreenShot.png')
,
<h1>
顯示smode(='ScreenShot.png') <img>
的src
onclick
處理程序,但實際上不會打開模式! onclick
處理程序在上面的步驟1.4中被覆蓋(它被覆蓋,沒有添加),而新的事件處理程序( btn.onclick = function() { modal.style.display = "block"; }
)僅使模態可見但不更改圖像源。 如果只設置一次onclick
處理程序,將會更容易。 這是一個解決方案。
JS-
function openModal(imgSrc)
{
document.getElementById("myImage").src = imgSrc;
document.getElementById("myModal").style.display = "block";
}
function closeModal() {
document.getElementById('myModal').style.display = "none";
}
// When the user clicks anywhere outside of the modal, close it
window.onclick = function(event) {
if (event.target == document.getElementById('myModal')) {
closeModal();
}
}
HTML-
<input type="image" src="….png" width="400" height="300"
alt="ScreenShot" onclick="openModal('….png');">
…
<span class="close" onclick="closeModal()">
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.