[英]Merge two hashes with arrays by the same key Ruby
我需要Ruby的幫助。 我有兩個從JSON解析出來的哈希值。 我使用以下代碼來解析文件:
document = JSON.load File.new("hosts.txt")
file = JSON.load File.new("admins.txt")
結果就是這樣的兩個大哈希值:
document={"total"=>13, "subtotal"=>13, "page"=>1, "per_page"=>20,
"search"=>nil, "sort"=>{"by"=>nil, "order"=>nil},
"results"=>[
{"ip"=>"10", "environment_id"=>7,
"medium_id"=>nil, "name"=>"one", "id"=>1},
{"ip"=>"15", "environment_id"=>7,
"medium_id"=>nil, "name"=>"two", "id"=>1},
{"ip"=>"10.5", "environment_id"=>6,
"medium_id"=>nil, "name"=>"four", "id"=>1}]}
file={"admins"=>[
{"name"=>"one", "surname"=>"Mark", "email"=>"mark@o.com"},
{"name"=>"two", "surname"=>"Adam", "email"=>"Adam@o.com"},
{"name"=>"four", "surname"=>"Ami", "email"=>"Ami@o.com"}]}
從第一個哈希中,我只需要來自結果鍵的信息,因此我已經完成了
data = document["results"]
對於第二個哈希,我已經做了同樣的事情:
people = file["admins"]
現在,當“名稱”值相同時,我想將姓和電子郵件從人員數組移到數據數組,並使用另一個哈希,如下所示:
new = {"all_data"=>[
{"ip"=>"10", "environment_id"=>7, "medium_id"=>nil,
"name"=>"one", "id"=>1, "surname"=>"Mark", "email"=>"mark@o.com"},
{"ip"=>"15", "environment_id"=>7, "medium_id"=>nil,
"name"=>"two", "id"=>1, "surname"=>"Adam", "email"=>"Adam@o.com"},
{"ip"=>"10.5", "environment_id"=>6, "medium_id"=>nil,
"name"=>"four", "id"=>1, "surname"=>"Ami", "email"=>"Ami@o.com"}]}
您能幫我做到這一點並解釋它如何工作嗎?
personal_data = file['admins'].map(&:dup)
.group_by { |e| e.delete('name') }
上面的dup
/ delete
技巧不是必需的,因為在任何情況下都可以正確處理下面的merge
,但這是出於語義清晰的目的。
document['results'].map do |h|
h.merge(personal_data[h['name']].first) if personal_data[h['name']]
end
#⇒ [
# {"ip"=>"10", "environment_id"=>7, "medium_id"=>nil, "name"=>"one",
# "id"=>1, "surname"=>"Mark", "email"=>"mark@o.com"},
# {"ip"=>"15", "environment_id"=>7, "medium_id"=>nil, "name"=>"two",
# "id"=>1, "surname"=>"Adam", "email"=>"Adam@o.com"},
# {"ip"=>"10.5", "environment_id"=>6, "medium_id"=>nil, "name"=>"four",
# "id"=>1, "surname"=>"Ami", "email"=>"Ami@o.com"}]
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